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Misalkan f ( x ) = − x − 9 dan g ( x ) = 3 1 ​ x + 4 , tentukanlah : ( ( f ∘ g ) − 1 ) − 1 ( x )

Misalkan   dan , tentukanlah :
 

  

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R. Novianto

Master Teacher

Mahasiswa/Alumni Universitas Tanjungpura Pontianak

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Pembahasan

Diketahui : Ditanya : = .... Penyelesaian : Sifat invers pada komposisi fungsi maka, Jadi,

Diketahui :
begin mathsize 14px style straight f open parentheses straight x close parentheses equals negative straight x minus 9 end style 
begin mathsize 14px style straight g open parentheses straight x close parentheses equals 1 third straight x plus 4 end style

Ditanya : begin mathsize 14px style open parentheses open parentheses straight f ring operator straight g close parentheses to the power of negative 1 end exponent close parentheses to the power of negative 1 end exponent open parentheses straight x close parentheses end style = ....

Penyelesaian :

Sifat invers pada komposisi fungsi
 

begin mathsize 14px style open parentheses straight f ring operator straight g close parentheses to the power of negative 1 end exponent open parentheses straight x close parentheses equals open parentheses straight g to the power of negative 1 end exponent ring operator straight f to the power of negative 1 end exponent close parentheses open parentheses straight x close parentheses open parentheses straight f to the power of negative 1 end exponent close parentheses to the power of negative 1 end exponent open parentheses straight x close parentheses equals straight f open parentheses straight x close parentheses end style  
 

maka, 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell open parentheses open parentheses straight f ring operator straight g close parentheses to the power of negative 1 end exponent close parentheses to the power of negative 1 end exponent open parentheses straight x close parentheses end cell equals cell open parentheses straight g to the power of negative 1 end exponent ring operator straight f to the power of negative 1 end exponent close parentheses to the power of negative 1 end exponent open parentheses straight x close parentheses end cell row blank equals cell open parentheses open parentheses straight f to the power of negative 1 end exponent close parentheses to the power of negative 1 end exponent ring operator open parentheses straight g to the power of negative 1 end exponent close parentheses to the power of negative 1 end exponent close parentheses open parentheses straight x close parentheses end cell row blank equals cell open parentheses straight f ring operator straight g close parentheses open parentheses straight x close parentheses end cell row blank equals cell straight f open parentheses straight g open parentheses straight x close parentheses close parentheses end cell row blank equals cell negative open parentheses straight g open parentheses straight x close parentheses close parentheses minus 9 end cell row blank equals cell negative open parentheses 1 third straight x plus 4 close parentheses minus 9 end cell row blank equals cell negative 1 third straight x minus 4 minus 9 end cell row blank equals cell negative 1 third straight x minus 13 end cell end table end style 

Jadi, begin mathsize 14px style left parenthesis open parentheses straight f ring operator straight g close parentheses to the power of negative 1 end exponent right parenthesis to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals negative 1 third straight x minus 13 end style 
 

 

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