Iklan

Pertanyaan

Lengkapi data tabel berikut :

Lengkapi data tabel berikut :


Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

15

:

17

:

57

Klaim

Iklan

S. Lubis

Master Teacher

Jawaban terverifikasi

Jawaban

data yang lengkap sesuai tabel diatas.

data yang lengkap sesuai tabel diatas.

Pembahasan

Pembahasan
lock

Berdasarkan data tabel, nilai 0,01 dan 0,005 menunjukkan data konsentrasi asam dengan satuan molar (M). Penentuan pH asam kuat dapat dihitung dengan menggunakan rumus berikut. 1. 0,01 M HI. 2. 0,005 M . 3. HCl dengan pH = 4. Berdasarkan perhitungan diatas, data menjadi lengkap sesuai pada tabel di bawah ini. Jadi, data yang lengkap sesuai tabel diatas.

Berdasarkan data tabel, nilai 0,01 dan 0,005 menunjukkan data konsentrasi asam dengan satuan molar (M).

Penentuan pH asam kuat dapat dihitung dengan menggunakan rumus berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell a cross times M end cell row blank blank cell a colon space jumlah space H to the power of plus sign end cell row blank blank cell M colon space konsentrasi space molar end cell row blank blank blank row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell end table end style 

1. 0,01 M HI.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell H I end cell rightwards arrow cell H to the power of plus sign and I to the power of minus sign space left parenthesis a colon 1 right parenthesis end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell a cross times M end cell row blank equals cell 1 cross times 0 comma 01 end cell row blank equals cell 10 to the power of negative sign 2 end exponent end cell row blank blank blank row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log space 10 to the power of negative sign 2 end exponent end cell row blank equals 2 end table end style 

2. 0,005 M begin mathsize 14px style H subscript 2 S O subscript 4 end style.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell H subscript 2 S O subscript 4 end cell rightwards arrow cell 2 H to the power of plus sign and S O subscript 4 to the power of 2 minus sign space left parenthesis a colon 2 right parenthesis end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell a cross times M end cell row blank equals cell 2 cross times 0 comma 005 end cell row blank equals cell 10 to the power of negative sign 2 end exponent end cell row blank blank blank row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log space 10 to the power of negative sign 2 end exponent end cell row blank equals 2 end table end style 

3. HCl dengan pH = 4.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals 4 row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign pH end exponent end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 4 end exponent end cell row blank blank blank row cell H Cl end cell rightwards arrow cell H to the power of plus sign plus Cl to the power of negative sign space end exponent left parenthesis a colon 1 right parenthesis end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell a cross times M end cell row M equals cell fraction numerator open square brackets H to the power of plus sign close square brackets over denominator a end fraction end cell row blank equals cell 10 to the power of negative sign 4 end exponent over 1 end cell row blank equals cell 10 to the power of negative sign 4 end exponent end cell row blank equals cell 0 comma 0001 space M end cell end table end style 

Berdasarkan perhitungan diatas, data menjadi lengkap sesuai pada tabel di bawah ini.
 

Jadi, data yang lengkap sesuai tabel diatas.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

Iklan

Pertanyaan serupa

Larutan H 2 ​ SO 4 ​ 0,01 M mempunyai pH ....

3

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia