Larutan yang mengandung ion Cl− dan Br− dengan konsentrasi masing-masing 0,020 M ditambahi larutan AgNO3​ tetes demi tetes. Hitunglah konsentrasi ion Ag+ yang terdapat dalam larutan agar terjadi endapan AgBr, sedangkan AgCl belum mengendap. Diketahui Ksp​ AgCl=1,61×10−10 dan Ksp​ AgBr=7,7×10−13.

Pertanyaan

Larutan yang mengandung ion begin mathsize 14px style Cl to the power of minus sign space dan space Br to the power of minus sign end style dengan konsentrasi masing-masing 0,020 M ditambahi larutan begin mathsize 14px style Ag N O subscript 3 end style tetes demi tetes. Hitunglah konsentrasi ion begin mathsize 14px style Ag to the power of plus sign end style yang terdapat dalam larutan agar terjadi endapan AgBr, sedangkan AgCl belum mengendap. Diketahui begin mathsize 14px style K subscript sp space Ag Cl equals 1 comma 61 cross times 10 to the power of negative sign 10 end exponent end style dan begin mathsize 14px style K subscript sp space Ag Br equals 7 comma 7 cross times 10 to the power of negative sign 13 end exponent end style.
 

A. Budi

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

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Pembahasan

begin mathsize 14px style Ag Br open parentheses s close parentheses equilibrium Ag to the power of plus sign open parentheses aq close parentheses and Br to the power of minus sign open parentheses aq close parentheses K subscript sp equals open square brackets Ag to the power of plus sign close square brackets open square brackets Br to the power of minus sign close square brackets 7 comma 7 cross times 10 to the power of negative sign 13 end exponent equals open square brackets Ag to the power of plus sign close square brackets open parentheses 0 comma 02 close parentheses open square brackets Ag to the power of plus sign close square brackets equals 3 comma 85 cross times 10 to the power of negative sign 11 end exponent space M open square brackets Ag to the power of plus sign close square brackets greater than 3 comma 85 cross times 10 to the power of negative sign 11 end exponent space M space akan space terbentuk space endapan space Ag Br  Ag Cl open parentheses s close parentheses equilibrium Ag to the power of plus sign open parentheses aq close parentheses and Cl to the power of minus sign open parentheses aq close parentheses K subscript sp equals open square brackets Ag to the power of plus sign close square brackets open square brackets Cl to the power of minus sign close square brackets 1 comma 61 cross times 10 to the power of negative sign 10 end exponent equals open square brackets Ag to the power of plus sign close square brackets open parentheses 0 comma 02 close parentheses open square brackets Ag to the power of plus sign close square brackets equals 8 comma 05 cross times 10 to the power of negative sign 9 end exponent space M open square brackets Ag to the power of plus sign close square brackets less than 8 comma 05 cross times 10 to the power of negative sign 9 end exponent space M space tidak space akan space terbentuk space endapan space Ag Cl space  3 comma 85 cross times 10 to the power of negative sign 11 end exponent space M less than open square brackets Ag to the power of plus sign close square brackets less than 8 comma 05 cross times 10 to the power of negative sign 9 end exponent space M end style

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