Pertanyaan

Larutan NH 3 0,2 M (Kb = 1 × 10 -5 ) sebanyak 50 mL ditambahkan ke dalam 50 mL larutan HCl 0,2 M sehingga terjadi reaksi: NH 3 ( aq ) + HC l ( aq ) → NH 4 C l ( aq ) ( Kw = 1 0 − 14 ) . Harga pH larutan tersebut adalah ….

Larutan NH₃ 0,2 M (Kb = 1 × 10^-5) sebanyak 50 mL ditambahkan ke dalam 50 mL larutan HCl 0,2 M sehingga terjadi reaksi: $NH_{3} (aq) + HC l (aq) \to NH_{4} C l (aq) (Kw = 1 0^{- 14}) .$

Harga pH larutan tersebut adalah ….

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S. Utari

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Pembahasan

$Mol space NH subscript 3 space end subscript equals space straight M space cross times straight V space equals 0 comma 2 space straight M space cross times 50 space mL space equals space 10 space mmol Mol space HCl space equals space straight M space cross times straight V space equals space 0 comma 2 space straight M space cross times 50 space mL space equals space 10 space mmol space space space space space space space space space space space space space space space space space space space space NH subscript 3 space end subscript space space space space space space space space space plus space HCl space space space space space space space space space space space space rightwards arrow NH subscript 4 Cl Mula space space space space space space space space space space space 10 space mmol space space space space space space space 10 space mmol space space space space space Reaksi space space space space space space space 10 space mmol space space space space space space space 10 space mmol space space space space space space space space space 10 space mmol Sisa space space space space space space space space space space space space space space 0 space mmol space space space space space space space space space 0 space mmol space space space space space space space space space 10 space mmol left square bracket NH subscript 4 Cl right square bracket space equals space fraction numerator m o l over denominator V t o t a l end fraction equals fraction numerator 10 space m m o straight l over denominator 100 space m L end fraction equals 0 comma 1 space straight M NH subscript 4 Cl space merupakan space garam space asam comma space sehingga colon left square bracket straight H to the power of plus right square bracket equals space square root of fraction numerator Kw cross times left square bracket garam right square bracket over denominator Kb end fraction end root equals square root of fraction numerator 10 to the power of negative 14 end exponent cross times left square bracket 0 comma 1 right square bracket over denominator 10 to the power of negative 5 end exponent end fraction end root equals square root of 10 to the power of negative 10 end exponent end root equals 10 to the power of negative 5 end exponent straight M pH equals negative space log space 10 to the power of negative 5 end exponent straight M equals 5$

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