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Larutan NaX 0,1 M terhidrolisis 10%. Hitunglah tetapan kesetimbangan reaksi ( K h ​ ) tersebut dan pH larutannya.

Larutan NaX 0,1 M terhidrolisis 10%. Hitunglah tetapan kesetimbangan reaksi  tersebut dan pH larutannya.

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N. Puspita

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah dan p H=8.

jawaban yang benar adalah begin mathsize 14px style K subscript italic h bold equals bold 10 to the power of bold minus sign bold 11 end exponent end style dan pH=8.

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Pembahasan

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Larutan NaX merupakan garam yang bersifat basa denganderajat ionisasi Menghitung nilai : Menghitung nilai p H: Jadi jawaban yang benar adalah dan p H=8.

Larutan NaX merupakan garam yang bersifat basa dengan derajat ionisasi begin mathsize 14px style open parentheses alpha close parentheses equals 10 percent sign equals 0 comma 1 end style 

Menghitung nilai begin mathsize 14px style K subscript h end style:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell alpha squared space end cell equals cell space K subscript a over M end cell row cell left parenthesis 0 comma 1 right parenthesis squared space end cell equals cell space fraction numerator K subscript a over denominator 0 comma 1 end fraction end cell row cell 0 comma 01 space end cell equals cell space fraction numerator K subscript a over denominator 0 comma 1 end fraction end cell row cell K subscript a space end cell equals cell space 0 comma 01 cross times 0 comma 1 end cell row cell K subscript a space end cell equals cell space 0 comma 001 end cell row cell K subscript a space end cell equals cell space 10 to the power of negative sign 3 end exponent end cell end table end style  

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript h space end cell equals cell space K subscript w over K subscript a end cell row blank equals cell space 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 3 end exponent end cell row blank equals cell space 10 to the power of negative sign 11 end exponent end cell end table end style 

Menghitung nilai pH:

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets space end cell equals cell space square root of K subscript h cross times open square brackets X to the power of minus sign close square brackets end root end cell row blank equals cell space square root of 10 to the power of negative sign 11 end exponent cross times 10 to the power of negative sign 1 end exponent end root end cell row blank equals cell space square root of 10 to the power of negative sign 12 end exponent end root end cell row blank equals cell space 10 to the power of negative sign 6 end exponent end cell end table   

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic p O H space end cell equals cell space minus sign log space open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell negative sign log space 10 to the power of negative sign 6 end exponent end cell row blank equals cell space 6 end cell end table end style   

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic p H space end cell equals cell space 14 space minus sign space italic p O H end cell row blank equals cell space 14 space minus sign space 6 end cell row blank equals cell space 8 end cell end table end style   

Jadi jawaban yang benar adalah begin mathsize 14px style K subscript italic h bold equals bold 10 to the power of bold minus sign bold 11 end exponent end style dan pH=8.

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