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Larutan NaCl 0,01 M sebanyak 100 mL dicampur denga...

Larutan NaCl 0,01 M sebanyak 100 mL dicampur dengan 200 mL larutan NaCl 0,005 M dan 200 mL larutan CaCl2 0,01 M. Berapakah molaritas ion Cl- setelah pencampuran ?

Jawaban:

Hitung mol Cl pada setiap larutan

Larutan pertama,

begin mathsize 14px style mol space Na Cl double bond M middle dot V space space space space space space space space space space space space space space space equals 0 comma 01 middle dot 100 space space space space space space space space space space space space space space space equals 1 mmol end style 

begin mathsize 14px style Na Cl space space space space space space rightwards arrow space space Na to the power of plus sign space space space space space plus space space space space Cl to the power of minus sign 1 mmol space space space space space space space space space 1 mmol space space space space space space space 1 mmol end style 

begin mathsize 14px style mol space Cl to the power of minus sign equals 1 space mmol end style 

Larutan kedua,

begin mathsize 14px style mol space Na Cl double bond M middle dot V space space space space space space space space space space space space space space space equals 0 comma 005 middle dot 200 space space space space space space space space space space space space space space space equals 1 mmol end style  

begin mathsize 14px style Na Cl space space space space space space rightwards arrow space space Na to the power of plus sign space space space space space plus space space space space Cl to the power of minus sign 1 mmol space space space space space space space space space 1 mmol space space space space space space space 1 mmol end style 

begin mathsize 14px style mol space Cl to the power of minus sign equals 1 space mmol space end style 

Larutan ketiga,

begin mathsize 14px style mol space Ca Cl subscript 2 double bond M middle dot V space space space space space space space space space space space space space space space equals 0 comma 01 middle dot 200 space space space space space space space space space space space space space space space equals 2 space mmol end style  

begin mathsize 14px style Ca Cl subscript 2 space space space space space space rightwards arrow space space Ca to the power of 2 plus sign space space space space space plus space space space space 2 Cl to the power of minus sign 2 mmol space space space space space space space space space 2 mmol space space space space space space space space space space space 4 mmol end style 

begin mathsize 14px style mol space Cl to the power of minus sign equals 4 space mmol space end style 

konsentrasi klorida total,

begin mathsize 14px style mol space Cl to the power of minus sign subscript open parentheses total close parentheses end subscript equals 1 plus 1 plus 4 space space space space space space space space space space space space space space space space space space space space space space equals 6 space mmol  open square brackets Cl to the power of minus sign close square brackets equals fraction numerator 6 mmol over denominator 500 mL end fraction space space space space space space space space space equals 0 comma 012 space M end style 

Jadi molaritas ion klorida adalah 0,012 M 

 

 

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