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Pertanyaan

Larutan basa lemah tepat jenuh L ( OH ) 2 ​ mempunyai pH = 10, tentukan K sp ​ basa tersebut? ​

Larutan basa lemah tepat jenuh  mempunyai pH = 10, tentukan basa tersebut?

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J. Siregar

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

Jawaban

basa lemah adalah .

 K subscript sp basa lemah L open parentheses O H close parentheses subscript 2 adalah 5 cross times 10 to the power of negative sign 13 end exponent.

Pembahasan

adalah basa lemah yang sukar larut. Penentuan dapat dihitung berdasarkan hubungan kelarutan dan pH. Jadi, basa lemah adalah .

L open parentheses O H close parentheses subscript 2 adalah basa lemah yang sukar larut. Penentuan K subscript sp dapat dihitung berdasarkan hubungan kelarutan dan pH.

table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell 14 minus sign pH end cell row blank equals cell 14 minus sign 10 end cell row blank equals 4 row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign pOH end exponent end cell row blank equals cell 10 to the power of negative sign 4 end exponent end cell row blank blank blank row cell L open parentheses O H close parentheses subscript 2 end cell rightwards harpoon over leftwards harpoon cell L to the power of 2 plus sign and 2 O H to the power of minus sign end cell row cell open square brackets L to the power of 2 plus sign close square brackets end cell equals cell 1 half cross times open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell 1 half cross times 10 to the power of negative sign 4 end exponent end cell row blank equals cell 5 cross times 10 to the power of negative sign 5 end exponent end cell row cell K subscript sp end cell equals cell open square brackets L to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row blank equals cell left parenthesis 5 cross times 10 to the power of negative sign 5 end exponent right parenthesis left parenthesis 10 to the power of negative sign 4 end exponent right parenthesis squared equals 5 cross times 10 to the power of negative sign 13 end exponent end cell end table 


Jadi, K subscript sp basa lemah L open parentheses O H close parentheses subscript 2 adalah 5 cross times 10 to the power of negative sign 13 end exponent.

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