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Larutan basa lemah tepat jenuh  mempunyai pH = 10....

Larutan basa lemah tepat jenuh Mg open parentheses O H close parentheses subscript 2 mempunyai pH = 10. Ksp basa tersebut adalah.... 

  1. 5 cross times 10 to the power of negative sign 12 end exponent 

  2. 4 cross times 10 to the power of negative sign 12 end exponent 

  3. 2 cross times 10 to the power of negative sign 12 end exponent 

  4. 5 cross times 10 to the power of negative sign 13 end exponent 

  5. 5 cross times 10 to the power of negative sign 14 end exponent  

Jawaban:

Untuk menentukan Ksp Mg open parentheses O H close parentheses subscript 2 dari pH larutan yang diketahui, dengan cara :

1) Tentukan open square brackets O H to the power of minus sign close square brackets dari pH Mg open parentheses O H close parentheses subscript 2 yang diketahui

pH space Mg open parentheses O H close parentheses subscript 2 equals 10 pH and pOH equals 14 pOH equals 14 minus sign 10 pOH equals 4 pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets 4 equals minus sign log space open square brackets O H to the power of minus sign close square brackets open square brackets O H to the power of minus sign close square brackets equals 10 to the power of negative sign 4 end exponent space M 

2) Masukkan nilai kelarutan (molaritas)  open square brackets O H to the power of minus sign close square brackets ke rumus Ksp :

Mg open parentheses O H close parentheses subscript 2 subscript open parentheses s close parentheses end subscript rightwards harpoon over leftwards harpoon Mg to the power of 2 plus sign subscript open parentheses italic a italic q close parentheses end subscript plus 2 O H to the power of minus sign subscript open parentheses italic a italic q close parentheses end subscript space space space space space space space space space space space space space space space space space space space space begin inline style 1 half end style cross times 10 to the power of negative sign 4 end exponent space M space space space space 10 to the power of negative sign 4 end exponent space M K subscript sp equals open square brackets Mg to the power of 2 plus sign close square brackets middle dot open square brackets O H to the power of minus sign close square brackets to the power of negative sign 2 end exponent space space space space space equals open parentheses begin inline style 1 half cross times 10 to the power of negative sign 4 end exponent end style close parentheses open parentheses begin inline style 10 to the power of negative sign 4 end exponent end style close parentheses squared space space space space space equals 5 begin inline style cross times end style begin inline style 10 to the power of negative sign 13 end exponent end style  

Ksp basa tersebut adalah 5 begin inline style cross times end style begin inline style 10 to the power of negative sign 13 end exponent end style.

Jadi, jawaban yang tepat adalah D

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