Pertanyaan

Larutan 100 mL HCl 0,8 M dicampur dengan 100 mL HCl 0,8 M, menurut reaksi: NH 3 ( aq ) + HCl ( aq ) → NH 4 Cl ( aq ) ( Kw = 1 0 − 14 , Kb NH 3 = 1 0 − 5 ) Harga pH larutah tersebut adalah ...

Larutan 100 mL HCl 0,8 M dicampur dengan 100 mL HCl 0,8 M, menurut reaksi:

$NH_{3} (aq) + HCl (aq) \to NH_{4} Cl (aq) (Kw = 1 0^{- 14}, Kb NH_{3} = 1 0^{- 5})$

Harga pH larutah tersebut adalah ...

5 - log 2
5 + log 2
9 - log 2
9 + log 2
12 + log 2

S. Utari

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

Pembahasan

$NH subscript 3 left parenthesis aq right parenthesis space space plus HCl left parenthesis aq right parenthesis rightwards arrow NH subscript 4 Cl left parenthesis aq right parenthesis 0 comma 8 space straight M space space space space space space space 0 comma 8 straight M space space space space 100 mL space space space space space 100 mL Ditanya colon space harga space pH space larutan space yang space terjadi ? NH subscript 3 left parenthesis aq right parenthesis space space space space space space space space space space space space space plus space space space space space space space space HCl left parenthesis aq right parenthesis space space space space space space space space space space rightwards arrow space space space space space space NH subscript 4 Cl left parenthesis aq right parenthesis 0 comma 8 space straight M space straight x space 100 space mL space space space space space 0 comma 8 space straight M space straight x space 100 space mL straight M equals 80 space mmol space space space space space space space space space space equals 80 space mmol space space space space space space space space space space space space space space space space space space space space space space space space space space minus straight R equals 80 space mmol space space space space space space space space space space space space space space 80 space mmol space space space space space space space space space space space space space space space space space space space space space space space space space 80 space mmol straight S equals space space minus space space space space space space space space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 80 space mmol Molaritas space garam equals fraction numerator mmol space garam over denominator volume space total end fraction equals fraction numerator 80 space mmol over denominator 200 space mL end fraction equals 0 comma 4 straight M Karena space semua space reaktan space habis comma space berarti space merupakan space campuran space hidrolisis. space Hidrolisis space dilihat space dari space sifat space yang space kuat comma space disini space yang space kuat space adalah space HCl space left parenthesis asam right parenthesis. Rumus space Hidrolisis space untuk space Garam space asam colon left square bracket straight H to the power of plus right square bracket equals square root of fraction numerator Kw space straight x space Molaritas space Garam space straight x space valensi right parenthesis over denominator Kb end fraction end root left square bracket straight H to the power of plus right square bracket equals square root of fraction numerator 10 to the power of negative 14 end exponent space straight x space 0 comma 4 space straight M space straight x space 1 over denominator 10 to the power of negative 5 end exponent end fraction end root left square bracket straight H to the power of plus right square bracket equals square root of 4 space straight x space 10 to the power of negative 10 end exponent end root left square bracket straight H to the power of plus right square bracket equals space 2 space straight x space 10 to the power of negative 5 end exponent pH equals negative log space left square bracket straight H to the power of plus right square bracket equals negative log space left square bracket 2 straight x 10 to the power of negative 5 end exponent right square bracket space space equals 5 minus log space 2$

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