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Pertanyaan

Larutan 100 mL NH subscript 3 0,8 M dicampur dengan 100 mL HCl 0,8 M, menurut reaksi:

NH subscript 3 left parenthesis aq right parenthesis plus HCl left parenthesis aq right parenthesis rightwards arrow NH subscript 4 Cl left parenthesis aq right parenthesis  left parenthesis Kw equals 10 to the power of negative 14 end exponent comma Kb space NH subscript 3 equals 10 to the power of negative 5 end exponent right parenthesis

Harga pH larutan tersebut adalah ...

  1. 5 - log 2

  2. 5 + log 2

  3. 9 - log 2

  4. 9 + log 2

  5. 12 + log 2

D. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

NH subscript 3 left parenthesis aq right parenthesis plus HCl left parenthesis aq right parenthesis rightwards arrow NH subscript 4 Cl left parenthesis aq right parenthesis  0 comma 8 space straight M space space space space space space space space 0 comma 8 space straight M  100 space mL space space space space space 100 space mL

Ditanya : harga pH larutan yang terjadi ?

NH subscript 3 left parenthesis aq right parenthesis space space space space space space space space plus space space space space space HCl left parenthesis aq right parenthesis rightwards arrow NH subscript 4 Cl left parenthesis aq right parenthesis  0 comma 8 straight M cross times 100 mL space space space space space space 0 comma 8 straight M cross times 100 mL  straight M equals 80 space mmol space space space space space space space space equals 80 space mmol  straight R equals 80 space mmol space space space space space space space space space space space space 80 space mmol space space space space space space space space space space space 80 space mmol  stack straight S equals negative space space space space space space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space 80 space mmol space space with bar on top  Molaritas space gram equals fraction numerator mmol space gram over denominator volume space total end fraction equals fraction numerator 80 space mmol over denominator 200 space mL end fraction equals 0 comma 4 space straight M

Karena semua reaktan habis, berarti merupakan campuran hidrolisis. Hidrolisis dilihat dari sifat yang kuat, disini yang kuat adalah HCl (asam).

Rumus Hidrolisis untuk Garam asam:

left square bracket H to the power of plus right square bracket equals square root of fraction numerator K w cross times M o l a r i t a s space G a r a m cross times v a l e n s i over denominator K b end fraction end root  left square bracket H to the power of plus right square bracket equals square root of fraction numerator 10 to the power of negative 14 end exponent cross times 0 comma 4 M cross times 1 over denominator 10 to the power of negative 5 end exponent end fraction end root  left square bracket H to the power of plus right square bracket equals square root of 4 cross times 10 to the power of negative 10 end exponent end root  left square bracket H to the power of plus right square bracket equals 2 cross times 10 to the power of negative 5 end exponent  p H equals negative log left square bracket H to the power of plus right square bracket equals negative log left square bracket 2 cross times 10 to the power of negative 5 end exponent right square bracket equals 5 minus log space 2

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