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Pertanyaan

Larutan begin mathsize 14px style N H subscript 4 O H end style 0,1 M terionisasi 1%. Tetapkan ionisasi basa begin mathsize 14px style K subscript b end style adalah ....

  1. begin mathsize 14px style 1 cross times 10 to the power of negative sign 6 end exponent end style

  2. begin mathsize 14px style 1 cross times 10 to the power of negative sign 5 end exponent end style

  3. begin mathsize 14px style 2 cross times 10 to the power of negative sign 5 end exponent end style

  4. begin mathsize 14px style 5 cross times 10 to the power of negative sign 5 end exponent end style

  5. begin mathsize 14px style 1 cross times 10 to the power of negative sign 4 end exponent end style

Y. Rochmawatie

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Larutan begin mathsize 14px style N H subscript 4 O H end style adalah basa lemah yang tidak terionisasi sempurna didalam air. Larutan begin mathsize 14px style N H subscript 4 O H space end style hanya terionisasi 1% yang artinya hanya 1% dari larutan undefined yang menjadi ion begin mathsize 14px style O H to the power of minus sign end style dan begin mathsize 14px style N H subscript 4 to the power of plus end style. Reaksi ionisasi undefined

begin mathsize 14px style N H subscript 4 O H yields N H subscript 4 to the power of plus plus O H to the power of minus sign end style

begin mathsize 14px style open square brackets NH subscript 4 OH close square brackets equals 0 comma 1 space straight M end style

Konsentrasi ion begin mathsize 14px style N H subscript 4 to the power of plus end style dan ion begin mathsize 14px style OH to the power of minus end style sama dengan konsentrasi begin mathsize 14px style N H subscript 4 O H end style yang terionisasi

begin mathsize 14px style open square brackets N H subscript 4 to the power of plus close square brackets equals open square brackets O H to the power of minus sign close square brackets equals 0 comma 1 space M cross times 1 percent sign end style

begin mathsize 14px style open square brackets N H subscript 4 to the power of plus close square brackets equals open square brackets O H to the power of minus sign close square brackets equals 0 comma 001 space M equals 10 to the power of negative sign 3 end exponent M end style

Konsentrasi undefined akan berkurang sebanyak 1%, maka

begin mathsize 14px style straight K subscript straight b equals fraction numerator open square brackets NH subscript 4 to the power of plus close square brackets open square brackets OH to the power of minus close square brackets over denominator open square brackets NH subscript 4 OH close square brackets end fraction end style

begin mathsize 14px style straight K subscript straight b equals fraction numerator open parentheses 10 to the power of negative 3 end exponent close parentheses open parentheses 10 to the power of negative 3 end exponent close parentheses over denominator 0 comma 099 end fraction end style

begin mathsize 14px style straight K subscript straight b equals 0 comma 00001 equals 1 cross times 10 to the power of negative 5 end exponent end style

Dengan demikian, jawaban yang tepat adalah B.

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