Larutan H2​SO4​ 0,02 M akan memberikan warna yang sama dengan larutan HA 0,2 M jika ditetesi indikator yang sama. Tetapan ionisasi (Ka​) HA adalah ....

Pertanyaan

Larutan begin mathsize 14px style H subscript 2 S O subscript 4 end style 0,02 M akan memberikan warna yang sama dengan larutan HA 0,2 M jika ditetesi indikator yang sama. Tetapan ionisasi begin mathsize 14px style left parenthesis K subscript italic a right parenthesis end style HA adalah ....

  1. begin mathsize 14px style 1 cross times 10 to the power of negative sign 3 end exponent end style

  2. begin mathsize 14px style 2 cross times 10 to the power of negative sign 3 end exponent end style

  3. begin mathsize 14px style 4 cross times 10 to the power of negative sign 3 end exponent end style

  4. begin mathsize 14px style 8 cross times 10 to the power of negative sign 3 end exponent end style

  5. begin mathsize 14px style 9 cross times 10 to the power of negative sign 3 end exponent end style

Y. Rochmawatie

Master Teacher

Jawaban terverifikasi

Pembahasan

Pembahasan

Tetapan ionisasi asam (begin mathsize 14px style K subscript a end style) menyatakan ukuran kekuatan dari suatu asam secara kuantitatif.

Diketahui

begin mathsize 14px style M subscript H subscript 2 S O subscript 4 end subscript equals space 0 comma 02 space M M subscript HA equals 0 comma 2 space M end style

Ditanya

Tetapan ionisasi begin mathsize 14px style open parentheses K subscript a close parentheses end style HA

Jawab

  • Nilai begin mathsize 14px style open square brackets H to the power of plus sign close square brackets space H subscript 2 S O subscript 4 end style

            begin mathsize 14px style H subscript 2 S O subscript 4 yields 2 H to the power of plus sign and S O subscript 4 to the power of 2 minus sign end exponent end style

            a = Jumlah ion begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style = 2

            begin mathsize 14px style open square brackets H to the power of plus sign close square brackets double bond a middle dot M open square brackets H to the power of plus sign close square brackets equals 2 middle dot 0 comma 02 open square brackets H to the power of plus sign close square brackets equals 0 comma 04 open square brackets H to the power of plus sign close square brackets equals 4 middle dot 10 to the power of negative sign 2 end exponent end style 

  • pH larutan begin mathsize 14px style H subscript 2 S O subscript 4 end style

            begin mathsize 14px style pH equals minus sign log space open square brackets H to the power of plus sign close square brackets pH equals minus sign log space 4 middle dot 10 to the power of negative sign 2 end exponent pH equals 2 minus sign log space 4 end style 

  • pH larutan HA

            Larutan undefined memberikan warna yang sama dengan larutan HA, maka pH kedua larutan ini sama.

            begin mathsize 14px style pH space H subscript 2 S O subscript 4 space equals space pH space HA space equals space 2 minus sign log space 4 end style

  • Konsentrasi ion undefined HA

            begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row cell 2 minus sign log space 4 end cell equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell anti space log space 2 minus sign log space 4 end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 4 middle dot 10 to the power of negative sign 2 end exponent space M end cell end table end style 

  • Tetapan ionisasi HA

          begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a middle dot M end root end cell row cell 4 middle dot 10 to the power of negative sign 2 end exponent end cell equals cell square root of K subscript a middle dot 0 comma 2 end root end cell row cell open parentheses 4 middle dot 10 to the power of negative sign 2 end exponent close parentheses squared end cell equals cell left parenthesis square root of K subscript a middle dot 0 comma 2 end root right parenthesis squared space end cell row cell 16 middle dot 10 to the power of negative sign 4 end exponent end cell equals cell K subscript a middle dot 0 comma 2 end cell row cell K subscript a end cell equals cell fraction numerator 16 middle dot 10 to the power of negative sign 4 end exponent over denominator 2 middle dot 10 to the power of negative sign 1 end exponent end fraction end cell row cell K subscript a end cell equals cell 8 middle dot 10 to the power of negative sign 3 end exponent end cell end table end style 

Jadi, jawaban yang benar adalah D.

 

 

1rb+

4.4 (7 rating)

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Jawaban terverifikasi

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