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Kurva y = x 3 + 1 x 2 + 4 x + a ​ memotong asimtot datarnya sebanyak 2 kali jika….

Kurva  memotong asimtot datarnya sebanyak 2 kali jika….

  1. negative 1 less than a less than 1 comma space a not equal to 3

  2. negative 4 less than a less than 4 comma space a not equal to 3

  3. a less than 4 comma space a not equal to 3

  4. a less or equal than 4 comma space a not equal to 3

  5. space a greater than 2 comma space a not equal to 3

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I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

Sehingga asimtot datar nya adalah y = 0 atau sumbu x Karena kurva tersebut memotong sumbu x di dua titik berarti nilai Diskriminan dari fungsi kuadrat

space limit as x rightwards arrow infinity of fraction numerator x squared plus 4 x plus a over denominator x cubed plus 1 end fraction equals space 0

Sehingga asimtot datar nya adalah y = 0 atau sumbu x

Karena kurva tersebut memotong sumbu x di dua titik berarti nilai Diskriminan dari fungsi kuadrat

f open parentheses x close parentheses equals x squared plus 4 x plus a space haruslah space positif straight D equals straight B squared minus 4 AC greater than 0 4 squared minus 4 open parentheses 1 close parentheses open parentheses straight a close parentheses greater than 0 minus 4 straight a greater than negative 16 straight a less than 4

 

begin mathsize 14px style y equals fraction numerator x squared plus 4 x plus a over denominator x cubed plus 1 end fraction equals fraction numerator x squared plus 4 x plus a over denominator left parenthesis x plus 1 right parenthesis left parenthesis x squared minus x plus 1 right parenthesis end fraction Supaya space kurva space memotong space asimtot space datarnya space di space dua space titik comma space pembilang space dari space kurva space di space atas space tidak space boleh space habis space dibagi space left parenthesis straight x plus 1 right parenthesis. Misalkan space straight g left parenthesis straight x right parenthesis equals straight x squared plus 4 straight x plus straight a. Supaya space straight g left parenthesis straight x right parenthesis space tidak space habis space dibagi space left parenthesis straight x plus 1 right parenthesis space maka colon g left parenthesis negative 1 right parenthesis not equal to 0 left parenthesis negative 1 right parenthesis squared plus 4 left parenthesis negative 1 right parenthesis plus a not equal to 0 1 minus 4 plus a not equal to 0 a not equal to 3 end style

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