Roboguru

Ke dalam larutan  0,03 M ditambahkan larutan sampai mulai terbentuk endapan. Jika pH saat terbentuk endapan adalah 12, maka  ....

Pertanyaan

Ke dalam larutan begin mathsize 14px style Ca Cl subscript 2 end style 0,03 M ditambahkan larutan undefinedsampai mulai terbentuk endapan. Jika pH saat terbentuk endapan adalah 12, maka begin mathsize 14px style K subscript sp space Ca open parentheses O H close parentheses subscript 2 end style ....begin mathsize 14px style space end style 

Pembahasan Soal:

Pada saat mulai mengendap, nilai begin mathsize 14px style K subscript sp double bond Q subscript sp end style.

Dari soal, diketahui:

begin mathsize 14px style stack Ca Cl subscript 2 with 0 comma 03 space M below rightwards arrow stack Ca to the power of 2 plus sign with 0 comma 03 space M below plus 2 Cl to the power of minus sign end style 

pH saat terbentuk endapan sebesar 12. Berarti:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell 14 minus sign pH end cell row blank equals cell 14 minus sign 12 equals 2 end cell end table end style 
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row 2 equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 0 comma 01 space M end cell end table end style 
 

begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 rightwards harpoon over leftwards harpoon stack Ca to the power of 2 plus sign with 0 comma 03 space M below plus stack 2 O H to the power of minus sign with 0 comma 01 space M below end style 

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space Ca open parentheses O H close parentheses subscript 2 end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared equals left parenthesis 0 comma 03 right parenthesis left parenthesis 0 comma 01 right parenthesis squared end cell row blank equals cell 3 cross times 10 to the power of negative sign 6 end exponent end cell end table end style 


Jadi, nilai begin mathsize 14px style bottom enclose K subscript bold sp bold space Ca bold open parentheses O H bold close parentheses subscript bold 2 end enclose end style sebesar begin mathsize 14px style bottom enclose bold 3 bold cross times bold 10 to the power of bold minus sign bold 6 end exponent end enclose end style.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 15 Maret 2021

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