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Pertanyaan

Ke d a l am 100 m L l a r u tan B a ( N O 3 ​ ) , 0 , 01 M d i t ambahkan 100 m L l a r u tan N a 2 ​ C r O 4 ​ 0 , 01 M . J ika Ks p : B a C r O 4 ​ = 2 x 1 0 − 10 , ma ss a z a t y an g m e n g e n d a p a d a l ah .. ( A r : B a = 137 ; C r = 52 ; O = 16 )

  1. 5,06 gram

  2. 2,53 gram

  3. 0,253 gram

  4. 0,506 gram

  5. 0,001265 gram

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J. Siregar

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

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Pembahasan

R e a k s i space y a n g space t e r j a d i space a d a l a h  space space space space space space space space space space space space space space space space space space space B a open parentheses N O subscript 3 close parentheses subscript 2 space left parenthesis a q right parenthesis space space space space space plus space N a subscript 2 C r O subscript 4 space left parenthesis a q right parenthesis space space space rightwards arrow space B a C r O subscript 4 space left parenthesis s right parenthesis space space space plus space 2 space N a N O subscript 3 space left parenthesis a q right parenthesis  M u l a space space space space space space space space space space space space space space space space 1 space m m o l space space space space space space space space space space space space space space space space space space space space space 1 space m m o l  R e a k s i space space space space space space space space space space minus space 1 space m m o l space space space space space space space space space space space space space space space space space minus space 1 space m m o l space space space space space space space space space space space space plus 1 space m m o l space space space space space space space space space space space space space plus space 2 space m m o l  S i s a space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space 1 space m m o l space space space space space space space space space space space space space space space space 2 space m m o l    M a s s a space B a C r O subscript 4 space equals space m o l space x space M r  space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0 comma 001 space m o l space x space 253 space g divided by m o l  space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0 comma 253 space g r a m

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