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Kalsium dan magnesium dapat mengendap sebagai hidroksida, dalam suatu sample mengandung 0,01 M Ca 2 + dan 0,001 M Mg 2 + . Apakah mulai mengendap ketika sudah mengendap sempurna sebagai Mg ( OH ) 2 ​ ?

Kalsium dan magnesium dapat mengendap sebagai hidroksida, dalam suatu sample mengandung 0,01 M  dan 0,001 M . Apakah begin mathsize 14px style Ca to the power of 2 plus sign end style mulai mengendap ketika begin mathsize 14px style Mg to the power of 2 plus sign end style sudah mengendap sempurna sebagai ?

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ion akan mulai mengendap saat sudah mengendap sempurna.

ion Ca to the power of 2 plus sign akan mulai mengendap saat Mg to the power of 2 plus sign sudah mengendap sempurna .

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Pada soal seharusnya dilengkapi dengan nilai dari hidroksidanya. Nilai nya adalah : Pada saat mengendap sempurna, maka . pH saat mengendap sempurna Karena nilai , maka ion mengendap sempurna pada pH Pada saat mulai mengendap, pH saat mulai mengendap Ion mulai mengendap pada pH Jadi, ion akan mulai mengendap saat sudah mengendap sempurna.

Pada soal seharusnya dilengkapi dengan nilai K subscript sp dari hidroksidanya. Nilai K subscript sp nya adalah : K subscript sp space Ca open parentheses O H close parentheses subscript 2 equals 5 comma 0 cross times 10 to the power of negative sign 6 end exponent space space K subscript sp space Mg open parentheses O H close parentheses subscript 2 equals 5 comma 6 cross times 10 to the power of negative sign 12 end exponent
Pada saat mengendap sempurna, maka Q subscript sp greater than K subscript sp.
pH saat Mg to the power of 2 plus sign mengendap sempurna
Mg open parentheses O H close parentheses subscript 2 left parenthesis italic s right parenthesis equilibrium Mg to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus 2 O H to the power of minus sign left parenthesis italic a italic q right parenthesis Q subscript sp double bond open square brackets Mg to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared Q subscript sp end subscript greater than K subscript sp open square brackets Mg to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared greater than K subscript sp 0 comma 001 open square brackets O H to the power of minus sign close square brackets squared space space greater than 5 comma 6 cross times 10 to the power of negative sign 12 end exponent space space space space space space space space space space open square brackets O H to the power of minus sign close square brackets squared space space greater than fraction numerator 5 comma 6 cross times 10 to the power of negative sign 12 end exponent over denominator 0 comma 001 end fraction space space space space space space space space space space open square brackets O H to the power of minus sign close square brackets space space greater than square root of 5 comma 6 cross times 10 to the power of negative sign 9 end exponent end root space space space space space space space space space space open square brackets O H to the power of minus sign close square brackets space space greater than 7 comma 5 cross times 10 to the power of negative sign 5 end exponent  pOH equals minus sign log open square brackets O H to the power of minus sign close square brackets space space space space space space space equals minus sign log space 7 comma 5 cross times 10 to the power of negative sign 5 end exponent space space space space space space space equals 5 minus sign log space 7 comma 5 pH space equals 14 space minus sign space pOH space space space space space space equals 14 minus sign left parenthesis 5 minus sign log space 7 comma 5 right parenthesis space space space space space space equals 9 plus space log space 7 comma 5
Karena nilai Q subscript sp greater than K subscript sp, maka ion Mg to the power of 2 plus sign mengendap sempurna pada pHgreater than9 plus log 7 comma 5

Pada saat mulai mengendap, Q subscript sp double bond K subscript sp
pH saat Ca to the power of 2 plus sign mulai mengendap
Ca open parentheses O H close parentheses subscript 2 left parenthesis italic s right parenthesis equilibrium Ca to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus 2 O H to the power of minus sign left parenthesis italic a italic q right parenthesis Q subscript sp double bond open square brackets Ca to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared space Q subscript sp double bond K subscript sp open square brackets Ca to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared equals K subscript sp 0 comma 01 open square brackets O H to the power of minus sign close square brackets squared space space space equals space 5 comma 0 cross times 10 to the power of negative sign 6 end exponent space space space space space space space space space space open square brackets O H to the power of minus sign close square brackets squared space space equals fraction numerator 5 comma 0 cross times 10 to the power of negative sign 6 end exponent over denominator 0 comma 01 end fraction space space space space space space space space space space open square brackets O H to the power of minus sign close square brackets space space equals square root of 5 comma 0 cross times 10 to the power of negative sign 4 end exponent end root space space space space space space space space space space open square brackets O H to the power of minus sign close square brackets space space equals 2 comma 2 cross times 10 to the power of negative sign 2 end exponent  pOH equals minus sign log open square brackets O H to the power of minus sign close square brackets space space space space space space space equals minus sign log space 2 comma 2 cross times 10 to the power of negative sign 2 end exponent space space space space space space space equals 2 minus sign log space 2 comma 2 pH space equals 14 space minus sign space pOH space space space space space space equals 14 minus sign left parenthesis 2 minus sign log space 2 comma 2 right parenthesis space space space space space space equals 12 plus space log space 2 comma 2
Ion Ca to the power of 2 plus sign mulai mengendap pada pHequals12 plus log 2 comma 2

Jadi, ion Ca to the power of 2 plus sign akan mulai mengendap saat Mg to the power of 2 plus sign sudah mengendap sempurna .

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