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Jika p dan q adalah penyelesaian persamaan x 3 l o g x = 9. x − 5 , maka pq = …

Jika p dan q adalah penyelesaian persamaan , maka pq = …

  1. -2

  2. -5

  3. 1 over 9

  4. 1 over 81

  5. 1 over 243

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Pembahasan

Maka diperoleh: Sehingga: Penyelesaiannya yaitu dan , maka:

x to the power of log presubscript space presuperscript 3 invisible function application x end exponent equals 9. x to the power of negative 5 end exponent  log presubscript space presuperscript 3 invisible function application x to the power of log presubscript space presuperscript 3 invisible function application x end exponent equals log presubscript space presuperscript 3 invisible function application left parenthesis 9. x to the power of negative 5 end exponent right parenthesis  log presubscript space presuperscript 3 invisible function application x. log presubscript space presuperscript 3 invisible function application x equals log presubscript space presuperscript 3 invisible function application 9 plus log presubscript space presuperscript 3 invisible function application x to the power of negative 5 end exponent  log presubscript space presuperscript 3 invisible function application x. log presubscript space presuperscript 3 invisible function application x equals log presubscript space presuperscript 3 invisible function application 9 minus 5. log presubscript space presuperscript 3 invisible function application x to the power of space  open parentheses log presubscript space presuperscript 3 invisible function application x close parentheses squared plus 5. log presubscript space presuperscript 3 invisible function application x minus 2 equals 0

Maka diperoleh:
p plus q equals negative 5 over 1 equals negative 5p equals x subscript 1

Sehingga:

log presubscript space presuperscript 3 invisible function application x subscript 1 plus log presubscript space presuperscript 3 invisible function application x subscript 2 equals negative 5  log presubscript space presuperscript 3 invisible function application left parenthesis x subscript 1. x subscript 2 right parenthesis equals log presubscript space presuperscript 3 invisible function application 3 to the power of negative 5 end exponent  x subscript 1. x subscript 2 equals 1 over 3 to the power of 5

Penyelesaiannya yaitu p equals x subscript 1 dan q equals space x subscript 2, maka:

p. q equals 1 over 243

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