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Pertanyaan

Jika maka nilai dari x + y = ....

Jika begin mathsize 14px style open parentheses table row straight a 2 row 2 0 end table close parentheses open parentheses table row cell straight x plus 1 end cell row cell straight y minus 1 end cell end table close parentheses equals open parentheses table row cell negative 2 end cell row straight a end table close parentheses end style maka nilai dari x + y = ....

  1. begin mathsize 14px style negative 1 fourth open parentheses straight a squared minus 2 straight a plus 4 close parentheses end style 

  2. begin mathsize 14px style negative 4 open parentheses straight a squared minus 2 straight a plus 4 close parentheses end style 

  3. begin mathsize 14px style straight a squared minus 2 straight a plus 4 end style 

  4. begin mathsize 14px style negative straight a squared plus 2 straight a minus 4 end style 

  5. begin mathsize 14px style 2 straight a squared minus 4 straight a plus 8 end style 

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M. Robo

Master Teacher

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Pembahasan

Dari kesamaan matriks di atas, diperoleh Subtitusikan persamaan (1) ke persamaan (2) sehingga Maka

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row straight a 2 row 2 0 end table close parentheses open parentheses table row cell straight x plus 1 end cell row cell straight y minus 1 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 2 end cell row straight a end table close parentheses end cell row cell open parentheses table row cell straight a open parentheses straight x plus 1 close parentheses plus 2 open parentheses straight y minus 1 close parentheses end cell row cell 2 open parentheses straight x plus 1 close parentheses plus 0 open parentheses straight y minus 1 close parentheses end cell end table close parentheses end cell equals cell open parentheses table row cell negative 2 end cell row straight a end table close parentheses end cell row cell open parentheses table row cell ax plus straight a plus 2 straight y minus 2 end cell row cell 2 straight x plus 2 plus 0 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 2 end cell row straight a end table close parentheses end cell row cell open parentheses table row cell ax plus straight a plus 2 straight y minus 2 end cell row cell 2 straight x plus 2 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 2 end cell row straight a end table close parentheses end cell end table  

Dari kesamaan matriks di atas, diperoleh 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 2 straight x plus 2 end cell equals straight a row cell 2 straight x end cell equals cell straight a minus 2 end cell row blank blank cell straight a minus 2 end cell row straight x equals cell fraction numerator straight a minus 2 over denominator 2 end fraction horizontal ellipsis open parentheses 1 close parentheses end cell row blank blank blank row cell ax plus straight a plus 2 straight y minus 2 end cell equals cell negative 2 end cell row cell ax plus straight a plus 2 straight y end cell equals 0 row cell ax plus straight a end cell equals cell negative 2 straight y horizontal ellipsis left parenthesis 2 right parenthesis space end cell row blank blank blank end table end style 

Subtitusikan persamaan (1) ke persamaan (2) sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight a open parentheses fraction numerator straight a minus 2 over denominator 2 end fraction close parentheses plus straight a end cell equals cell negative 2 straight y end cell row cell fraction numerator straight a squared minus 2 straight a over denominator 2 end fraction plus straight a end cell equals cell negative 2 straight y end cell row cell straight a squared minus 2 straight a plus 2 straight a end cell equals cell negative 4 straight y end cell row cell straight a squared end cell equals cell negative 4 straight y end cell row straight y equals cell negative straight a squared over 4 end cell end table end style 

Maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight x plus straight y end cell equals cell fraction numerator straight a minus 2 over denominator 2 end fraction plus open parentheses negative straight a squared over 4 close parentheses end cell row blank equals cell fraction numerator 2 straight a minus 4 minus straight a squared over denominator 4 end fraction end cell row blank equals cell negative 1 fourth open parentheses straight a squared minus 2 straight a plus 4 close parentheses end cell end table end style 

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Meika Savira

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