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Pertanyaan

Jika , maka x 3 + 3 x = ....

Jika begin mathsize 14px style 18.9 to the power of x minus 1 end exponent minus 3 to the power of x plus 1 end exponent minus 5 equals 2 open parentheses 3 to the power of x minus 1 close parentheses end style , maka  = ....

  1. 1

  2. 4

  3. 17

  4. 54

  5. 145

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style 18 bullet 9 to the power of x minus 1 end exponent minus 3 to the power of x plus 1 end exponent minus 5 equals 2 open parentheses 3 to the power of x minus 1 close parentheses 18 bullet 9 to the power of x over 9 to the power of 1 minus 3 to the power of x bullet 3 to the power of 1 minus 5 equals 2 bullet 3 to the power of x minus 2 2 bullet 9 to the power of x minus 3 bullet 3 to the power of x minus 5 equals 2 bullet 3 to the power of x minus 2 2 bullet 9 to the power of x minus 5 bullet 3 to the power of x minus 3 equals 0 2 bullet open parentheses 3 to the power of x close parentheses squared minus 5 bullet 3 to the power of x minus 3 equals 0  text Misalkan  end text z equals 3 to the power of x text , maka end text 2 z squared minus 5 z minus 3 equals 0 open parentheses 2 z plus 1 close parentheses open parentheses z minus 3 close parentheses equals 0 z equals negative 1 half text  atau  end text z equals 3  text Untuk  end text z equals negative 1 half text , maka end text z equals negative 1 half 3 to the power of x equals negative 1 half  text Karena  end text 3 to the power of x greater than 0 comma space text maka tidak ada nilai x yang terpenuhi end text  text Untuk z=3, maka end text z equals 3 3 to the power of x equals 3 to the power of 1 x equals 1  text Maka end text x cubed plus 3 to the power of x equals 1 cubed plus 3 to the power of 1 equals 1 plus 3 equals 4 end style   

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Jika x adalah bilangan real yang memenuhi , maka 2 x 1 ​ − 2 − x 1 ​ = ....

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