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Jika diketahui K sp ​ Zn ( OH ) 2 ​ = 1 x 1 0 − 15 , tentukan kelarutan Zn ( OH ) 2 ​ dalam air murni!

Jika diketahui  , tentukan kelarutan dalam air murni!

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Y. Rochmawatie

Master Teacher

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begin mathsize 14px style Diketahui space bahwa space K subscript italic s italic p end subscript italic space dari space Zn open parentheses O H close parentheses subscript 2 space equals space 1 space x space 10 to the power of negative sign 15 end exponent space comma space kelarutannya space dalam air space murni space comma space maka space reaksi space ionisasinya space adalah Zn open parentheses O H close parentheses subscript 2 left parenthesis italic s italic right parenthesis space equilibrium Zn to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus space 2 O H to the power of minus sign left parenthesis italic a italic q right parenthesis s space space space space space space space space space space space space space space space space space space space s space space space space space space space space space space space space space space space space space space space space 2 s space space space space space space space space space space space space K subscript italic s italic p end subscript italic space equals space open square brackets Zn to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared space space 1 space x space 10 to the power of negative sign 15 end exponent space equals left parenthesis italic s right parenthesis left parenthesis 2 italic s right parenthesis squared space space space space space space space space space space space space space space space space space space space space space space space space space space 4 s cubed space equals space space 1 space x space 10 to the power of negative sign 15 end exponent space space space space space space space space space space space space space space space s space equals space cube root of fraction numerator 1 space x space 10 to the power of negative sign 15 end exponent over denominator 4 end fraction end root space space space space space space space space space space space space space space space space space s space equals 6 comma 30 space x space 10 to the power of negative sign 6 end exponent space mol forward slash liter  bold Maka bold comma bold space bold kelarutan bold space Zn bold open parentheses O H bold close parentheses subscript bold 2 bold space bold dalam bold space bold air bold space bold murni bold space bold adalah bold space bold space bold 6 bold comma bold 30 bold space italic x bold space bold 10 to the power of bold minus sign bold 6 end exponent bold space bold mol bold forward slash bold liter end style     

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