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Jika a 1 ​ dan memenuhi persamaan , maka a 1 ​ a 2 ​ adalah ….

Jika  dan size 14px a subscript size 14px 2 memenuhi persamaan begin mathsize 14px style open parentheses 2 log invisible function application a minus 1 close parentheses times fraction numerator 1 over denominator log presubscript blank presuperscript a invisible function application 10 end fraction equals log invisible function application 100 over a end style, maka  adalah ….

  1. -10

  2. -1

  3. 0,1

  4. 1

  5. 10

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Pembahasan

Misalkan log a = p, maka Sehingga saat p = -1, maka Saat p = 1, maka

begin mathsize 14px style open parentheses 2 log invisible function application a minus 1 close parentheses times fraction numerator 1 over denominator log presubscript blank presuperscript a invisible function application 10 end fraction equals log invisible function application 100 over a open parentheses 2 log invisible function application a minus 1 close parentheses times fraction numerator 1 over denominator log presubscript blank presuperscript a invisible function application 10 end fraction equals log invisible function application 100 minus log invisible function application a open parentheses 2 log invisible function application a minus 1 close parentheses times left parenthesis log invisible function application a right parenthesis equals 2 minus log invisible function application a end style 


Misalkan log a = p, maka

begin mathsize 14px style open parentheses 2 log invisible function application a minus 1 close parentheses times left parenthesis log invisible function application a right parenthesis equals 2 minus log invisible function application a open parentheses 2 p minus 1 close parentheses times p equals 2 minus p 2 p squared minus p equals 2 minus p 2 p squared minus p minus 2 plus p equals 0 2 p squared minus 2 equals 0 open parentheses 2 p plus 2 close parentheses open parentheses p minus 1 close parentheses equals 0 2 p equals negative 2 rightwards arrow p equals negative 1 space atau space p equals 1 end style 


Sehingga saat p = -1, maka

begin mathsize 14px style log invisible function application a equals negative 1 rightwards arrow a equals 1 over 10 end style 

Saat p = 1, maka

begin mathsize 14px style log invisible function application a equals 1 rightwards arrow a equals 10 a subscript 1 a subscript 2 equals 1 over 10 open parentheses 10 close parentheses equals 1 end style 

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Nilai x yang memenuhi persamaan adalah ….

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