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Jika f ( x ) = 3 x − 1 a x + 1 ​ , x  = 3 1 ​ , g ( x ) = x − 2 dan ( g − 1 ∘ f − 1 ) ( 2 ) = 2 7 ​ , hitunglah nilai a .

Jika  dan , hitunglah nilai 

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L. Rante

Master Teacher

Mahasiswa/Alumni Universitas Negeri Makassar

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nilai yang memenuhi adalah .

nilai begin mathsize 14px style straight a end style yang memenuhi adalah begin mathsize 14px style straight a equals 4 end style

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Pembahasan

Berdasarkan sifat invers fungsi komposisi maka artinya . Berdasarakan defenisi invers fungsimaka artinya . Sehingga Jadi nilai yang memenuhi adalah .

Berdasarkan sifat invers fungsi komposisi maka begin mathsize 14px style open parentheses g to the power of negative 1 end exponent ring operator f to the power of negative 1 end exponent close parentheses open parentheses 2 close parentheses equals 7 over 2 end style artinya begin mathsize 14px style open parentheses f ring operator g close parentheses to the power of negative 1 end exponent open parentheses 2 close parentheses equals 7 over 2 end style

Berdasarakan defenisi invers fungsi maka begin mathsize 14px style open parentheses f ring operator g close parentheses to the power of negative 1 end exponent open parentheses 2 close parentheses equals 7 over 2 end style artinya begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses 7 over 2 close parentheses equals 2 end style. Sehingga 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell g open parentheses x close parentheses end cell equals cell x minus 2 end cell row cell g open parentheses 7 over 2 close parentheses end cell equals cell 7 over 2 minus 2 end cell row cell g open parentheses 7 over 2 close parentheses end cell equals cell 3 over 2 end cell row blank blank blank row cell open parentheses f ring operator g close parentheses open parentheses 7 over 2 close parentheses end cell equals cell f open parentheses g open parentheses 7 over 2 close parentheses close parentheses end cell row 2 equals cell f open parentheses 3 over 2 close parentheses end cell row 2 equals cell fraction numerator straight a begin display style 3 over 2 end style plus 1 over denominator 3 open parentheses begin display style 3 over 2 end style close parentheses minus 1 end fraction end cell row 2 equals cell fraction numerator begin display style fraction numerator 3 straight a plus 2 over denominator 2 end fraction end style over denominator begin display style 9 over 2 end style minus 1 end fraction end cell row 2 equals cell fraction numerator begin display style fraction numerator 3 straight a plus 2 over denominator 2 end fraction end style over denominator begin display style 7 over 2 end style end fraction end cell row 2 equals cell fraction numerator 3 straight a plus 2 over denominator 7 end fraction end cell row cell 3 straight a plus 2 end cell equals 14 row cell 3 straight a end cell equals 12 row straight a equals cell 12 over 3 end cell row straight a equals 4 end table end style 

Jadi nilai begin mathsize 14px style straight a end style yang memenuhi adalah begin mathsize 14px style straight a equals 4 end style

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Jika f ( x ) = 2 1 ​ x + 4 dan g ( x ) = 3 x − 7 , hitunglah ( g − 1 ∘ f − 1 ) ( − 2 ) − ( f − 1 ∘ g − 1 ) ( − 2 ) .

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