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Jika  atom unsur X massanya 3 gram, massa atom relatif unsur tersebut adalah ...

Pertanyaan

Jika 3 comma 01 cross times 10 to the power of 22 atom unsur X massanya 3 gram, massa atom relatif unsur tersebut adalah ...

  1. 9,03 space 

  2. 15,05 space 

  3. 30 space 

  4. 60 space 

  5. 120 space 

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript X end cell equals cell fraction numerator Jumlah space atom over denominator 6 comma 02 cross times 10 to the power of 23 end fraction end cell row blank equals cell fraction numerator 3 comma 01 cross times 10 to the power of 22 over denominator 6 comma 02 cross times 10 to the power of 23 end fraction end cell row blank equals cell 0 comma 05 space mol end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell italic A subscript r space X end cell equals cell m over n end cell row blank equals cell fraction numerator 3 over denominator 0 comma 05 end fraction end cell row blank equals cell 60 space g space mol to the power of negative sign 1 end exponent end cell end table 

Jadi, jawaban yang benar adalah D.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

A. Chandra

Mahasiswa/Alumni Universitas Negeri Jakarta

Terakhir diupdate 30 April 2021

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Pertanyaan yang serupa

Lengkapilah tabel berikut.

Roboguru

Lengkapi tabel berikut ini!

Pembahasan Soal:

Langkah 1: Melengkapi tabel NO

1. Mol NO (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript NO end cell equals cell fraction numerator jumlah space partikel subscript NO over denominator L end fraction end cell row blank equals cell fraction numerator 6 comma 02 cross times 10 to the power of 23 space over denominator 6 comma 022 cross times 10 to the power of 23 end fraction end cell row blank equals cell 1 space mol end cell end table


2. Mr NO 

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript NO end cell equals cell Ar subscript N and Ar subscript O end cell row blank equals cell 14 plus 16 end cell row blank equals cell 30 space begin inline style bevelled gram over mol end style end cell end table


3. Massa NO (m)

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript NO end cell equals cell n subscript NO cross times Mr subscript NO end cell row blank equals cell 1 space mol space cross times 30 space begin inline style bevelled gram over mol end style end cell row blank equals cell 30 space gram end cell end table


4. Volume NO (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript NO end cell equals cell n subscript NO cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 1 space mol space cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 22 comma 4 space L end cell end table


5. Volume NO (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript NO end cell equals cell n subscript NO cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 1 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 24 space L end cell end table


Langkah 2: Melangkapi tabel H subscript bold 2 

1. Jumlah partikel H subscript bold 2 (x)

    table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times L end cell row blank equals cell 0 comma 1 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 6 comma 022 cross times 10 to the power of 22 space partikel end cell row blank blank blank end table

2. Mr H subscript bold 2

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript H subscript 2 end subscript end cell equals cell 2 cross times Ar subscript H end cell row blank equals cell 2 cross times 1 space begin inline style bevelled gram over mol end style end cell row blank equals cell 2 space begin inline style bevelled gram over mol end style end cell end table
 

3. Massa H subscript bold 2

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times Mr subscript H subscript 2 end subscript end cell row blank equals cell 0 comma 1 space mol space cross times 2 space begin inline style bevelled gram over mol end style end cell row blank equals cell 0 comma 2 space gram end cell end table


4. Volume H subscript bold 2 (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 1 space mol space cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 2 comma 24 space L end cell end table


5. Volume H subscript bold 2 (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 1 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 2 comma 4 space L end cell end table


Langkah 3: Melangkapi tabel N H subscript bold 3

1. mol N H subscript bold 3 (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript N H subscript 3 end subscript end cell equals cell fraction numerator V subscript STP subscript N H subscript 3 end subscript end subscript over denominator 22 comma 4 space bevelled L over mol end fraction end cell row blank equals cell fraction numerator 4 comma 48 space L over denominator 22 comma 4 space bevelled L over mol end fraction end cell row blank equals cell 0 comma 2 space mol end cell end table
 

2. Jumlah partikel N H subscript bold 3 (x)
     table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times L end cell row blank equals cell 0 comma 2 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 1 comma 2 cross times 10 to the power of 23 space partikel end cell end table


3. Mr N H subscript bold 3

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript N H subscript 3 end subscript end cell equals cell Ar subscript N plus left parenthesis 3 cross times Ar subscript H right parenthesis end cell row blank equals cell 14 space begin inline style bevelled gram over mol end style plus left parenthesis 3 cross times 1 space begin inline style bevelled gram over mol right parenthesis end style end cell row blank equals cell 17 space begin inline style bevelled gram over mol end style end cell end table
 

4. Massa N H subscript bold 3

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times Mr subscript N H subscript 3 end subscript end cell row blank equals cell 0 comma 2 space mol space cross times 17 space begin inline style bevelled gram over mol end style end cell row blank equals cell 3 comma 4 space gram end cell end table


5. Volume N H subscript bold 3 (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 2 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 4 comma 8 space L end cell end table


Langkah 4: Melangkapi tabel C H subscript 4

1. mol C H subscript 4 (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript C H subscript 4 end subscript end cell equals cell fraction numerator V subscript RTP subscript C H subscript 4 end subscript end subscript over denominator 24 space bevelled L over mol end fraction end cell row blank equals cell fraction numerator 12 comma 3 space L over denominator 24 space bevelled L over mol end fraction end cell row blank equals cell 0 comma 5125 space mol end cell end table 
 

2. Jumlah partikel C H subscript 4 (x)
     table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times L end cell row blank equals cell 0 comma 512 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 3 comma 08 cross times 10 to the power of 23 space partikel end cell end table


3. Mr C H subscript 4

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript C H subscript 4 end subscript end cell equals cell Ar subscript C plus left parenthesis 4 cross times Ar subscript H right parenthesis end cell row blank equals cell 12 space begin inline style bevelled gram over mol end style plus left parenthesis 4 cross times 1 space begin inline style bevelled gram over mol right parenthesis end style end cell row blank equals cell 16 space begin inline style bevelled gram over mol end style end cell end table
 

4. Massa C H subscript 4

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times Mr subscript C H subscript 4 end subscript end cell row blank equals cell 0 comma 512 space mol space cross times 16 space begin inline style bevelled gram over mol end style end cell row blank equals cell 8 comma 2 space gram end cell end table 


5. Volume C H subscript 4 (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 512 space mol cross times 22.4 space begin inline style bevelled L over mol end style end cell row blank equals cell 11 comma 48 space L end cell end table  


Dengan demikian, tabel lengkapnya adalah

Roboguru

Hitunglah massa masing-masing zat berikut:  molekul  (Ar S=32)

Pembahasan Soal:

Berikut adalah tahapan menentukan massa begin mathsize 14px style S subscript 8 end style :

1. Menentukan mol zat

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row X equals cell space n space x space L end cell row X equals cell jumlah space partikel end cell row n equals cell mol space zat end cell row L equals cell bilangan space Avogadro space left parenthesis 6 comma 02 x 10 to the power of 23 right parenthesis end cell end table end style 

Sehingga,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row n equals cell X over L end cell row blank equals cell fraction numerator 1 comma 204 x 10 to the power of 22 over denominator 6 comma 02 x 10 to the power of 23 end fraction end cell row blank equals cell 0 comma 2 space mol end cell end table end style 

2. Menentukan massa begin mathsize 14px style S subscript 8 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row m equals nxMr row m equals cell massa space zat open parentheses g close parentheses end cell row n equals cell mol space zat end cell row Mr equals cell massa space molekul space relatif left parenthesis g forward slash mol right parenthesis end cell end table end style 

Sehingga,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Mr space S subscript 8 end cell equals cell Ar space S space x space 8 end cell row blank equals cell 32 x 8 end cell row blank equals cell 256 space g forward slash mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell massa space S subscript 8 end cell equals cell 0 comma 2 space molx 256 space g forward slash mol end cell row blank equals cell 51 comma 2 space g end cell end table end style 

Berdasarkan perhitungan di atas, maka massa begin mathsize 14px style S subscript 8 end style adalah 51,2 g.

Roboguru

Sepotong kawat tembaga mengandung  atom . Tentukan massa kawat tembaga dalam kawat tersebut. Jika  = 63,5.

Pembahasan Soal:

Untuk mencari massa kawat tembaga (Cu), kita perlu cari terlebih dahulu molnya (n) melalui jumlah partikel yang diketahui di soal.

table attributes columnalign right center left columnspacing 0px end attributes row n equals cell fraction numerator jumlah space partikel over denominator L end fraction end cell row blank equals cell fraction numerator 3 comma 01 cross times 10 to the power of 23 over denominator 6 comma 02 cross times 10 to the power of 23 end fraction end cell row blank equals cell 1 half space mol end cell end table 

Hubungan mol dengan massa (m) adalah sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row m equals cell n cross times italic A subscript r end cell row blank equals cell 1 half cross times 63 comma 5 end cell row blank equals cell 31 comma 75 space gram end cell end table  

Jadi, massa kawat tembaga dalam kawat tersebut sebesar 31,75 gram.space  

Roboguru

Jika massa 1 atom C-12 = a gr, Massa atom relatif () dari N dan O berturut- turut adalah b sma dan c sma, berapakah massa 10 molekul gas nitrogen dioksida?

Pembahasan Soal:

Menentukan begin mathsize 14px style italic A subscript r end style unsur:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic A subscript r subscript N end cell equals cell fraction numerator m subscript N over denominator 1 over 12 cross times m subscript C minus sign 12 end subscript end fraction end cell row blank equals cell fraction numerator b over denominator 1 over 12 cross times a end fraction end cell row blank equals cell fraction numerator 12 b over denominator a end fraction end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic A subscript r subscript O end cell equals cell fraction numerator m subscript O over denominator 1 over 12 cross times m subscript C minus sign 12 end subscript end fraction end cell row blank equals cell fraction numerator c over denominator 1 over 12 cross times a end fraction end cell row blank equals cell fraction numerator 12 c over denominator a end fraction end cell end table end style 

Menentukan begin mathsize 14px style italic M subscript r space N O subscript 2 end style:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript N O subscript 2 end subscript end subscript end cell equals cell left parenthesis 1 cross times Ar space N right parenthesis plus left parenthesis 2 cross times Ar space O right parenthesis end cell row blank equals cell left parenthesis 1 cross times fraction numerator 12 b over denominator a end fraction right parenthesis plus left parenthesis 2 cross times fraction numerator 12 c over denominator a end fraction right parenthesis end cell row blank equals cell fraction numerator 12 b over denominator a end fraction plus fraction numerator 24 c over denominator a end fraction end cell row blank equals cell fraction numerator 12 left parenthesis b and 2 c right parenthesis over denominator a end fraction end cell end table end style 

Menentukan massa begin mathsize 14px style N O subscript 2 end style:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row n equals cell fraction numerator jumlah space molekul over denominator 6 comma 02 cross times 10 to the power of 23 end fraction end cell row blank equals cell fraction numerator 10 over denominator 6 comma 02 cross times 10 to the power of 23 end fraction end cell row blank equals cell 1 comma 66 cross times 10 to the power of negative sign 23 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript N O subscript 2 end subscript end cell equals cell n cross times Mr end cell row blank equals cell 1 comma 66 cross times 10 to the power of negative sign 23 end exponent cross times fraction numerator 12 left parenthesis b and 2 c right parenthesis over denominator a end fraction end cell row blank equals cell fraction numerator 19 comma 92 left parenthesis b and 2 c right parenthesis over denominator a end fraction cross times 10 to the power of negative sign 23 end exponent space gram end cell end table end style 

Jadi, massa begin mathsize 14px style N O subscript bold 2 end style yang benar adalah begin mathsize 14px style fraction numerator bold 19 bold comma bold 92 bold left parenthesis italic b bold plus bold 2 italic c bold right parenthesis over denominator italic a end fraction bold cross times bold 10 to the power of bold minus sign bold 23 end exponent bold space bold gram end style.

Roboguru

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