Jika 100 ml 0,1 M direaksikan dengan 200 ml 0,1 ...

Jika 100 ml $begin mathsize 14px style H Cl end style$ 0,1 M direaksikan dengan 200 ml $begin mathsize 14px style N H subscript 4 O H end style$ 0,1 M membentuk reaksi di bawah ini :

$begin mathsize 14px style H Cl and N H subscript 4 O H yields N H subscript 4 Cl and H subscript 2 O end style$

pH larutan di atas adalah .... $begin mathsize 14px style open parentheses Kb equals 1 cross times 10 to the power of negative sign 5 end exponent close parentheses end style$

Jawaban:

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell mol space H Cl end cell equals cell M cross times V end cell row blank equals cell 0 comma 1 space M cross times 100 space ml end cell row blank equals cell 10 space mmol end cell end table end style$

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell mol space N H subscript 4 O H end cell equals cell M cross times V end cell row blank equals cell 0 comma 1 space M cross times 200 space ml end cell row blank equals cell 20 space mmol end cell end table end style$

Larutan di atas termasuk larutan penyangga karena basa lemah tidak habis bereaksi.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript b cross times fraction numerator mol space basa space lemah over denominator mol space garam end fraction end cell row blank equals cell 10 to the power of negative sign 5 end exponent cross times fraction numerator 10 space mmol over denominator 10 space mmol end fraction end cell row blank equals cell 10 to the power of negative sign 5 end exponent end cell row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell negative sign log space 10 to the power of negative sign 5 end exponent end cell row blank equals 5 row pH equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign 5 end cell row blank equals 9 end table end style$

Jadi, pH larutan tersebut adalah 9.

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Download di Google Play

Download di Appstore

Produk Ruangguru

Produk Lainnya

Bantuan & Panduan

Hubungi Kami

081578200000

[email protected]

02140008000

Ikuti Kami

Instagram

Facebook

Twitter

Youtube