Iklan

Iklan

Pertanyaan

Hitunglah setiap ekspresi berikut. a, sin [ 2 cos − 1 ( 13 5 ​ ) ]

Hitunglah setiap ekspresi berikut.

a, 

Iklan

Y. Umi

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

Jawaban terverifikasi

Jawaban

.

 sin open square brackets 2 cos to the power of negative 1 end exponent open parentheses 5 over 13 close parentheses close square brackets equals 123 over 169.

Iklan

Pembahasan

Ingat! Jika , maka Akan dicari nilai dari . Jika , maka Dengan demikian, Jadi, .

Ingat!

Jika cos to the power of negative 1 end exponent space y equals x, maka y equals cos space x

Akan dicari nilai dari sin open square brackets 2 cos to the power of negative 1 end exponent open parentheses 5 over 13 close parentheses close square brackets. Jika cos to the power of negative 1 end exponent open parentheses 5 over 13 close parentheses equals x, maka 

table attributes columnalign right center left columnspacing 0px end attributes row cell cos space x end cell equals cell samping over miring end cell row blank equals cell 5 over 13 end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row depan equals cell square root of miring squared minus sign samping squared end root end cell row blank equals cell square root of 13 squared minus sign 5 squared end root end cell row blank equals cell square root of 169 minus sign 25 end root end cell row blank equals cell square root of 144 end cell row blank equals 12 end table

table attributes columnalign right center left columnspacing 0px end attributes row cell sin space italic x end cell equals cell depan over miring end cell row blank equals cell 12 over 13 end cell end table

Dengan demikian,

table attributes columnalign right center left columnspacing 0px end attributes row cell sin open square brackets 2 cos to the power of negative 1 end exponent open parentheses 5 over 13 close parentheses close square brackets end cell equals cell sin open parentheses 2 x close parentheses end cell row blank equals cell 2 times sin space x times cos space x end cell row blank equals cell 2 times 12 over 13 times 5 over 13 end cell row blank equals cell 123 over 169 end cell end table

Jadi, sin open square brackets 2 cos to the power of negative 1 end exponent open parentheses 5 over 13 close parentheses close square brackets equals 123 over 169.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

Iklan

Iklan

Pertanyaan serupa

Tentukanekspresi aljabar masing-masing ekspresi berikut. c. sin ( 2 cos − 1 x )

43

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia