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Hitunglah pH dari larutan penyangga berikut ini! e. 100 mL larutan NH 3 ​ 0,3M + 100 mL larutan H 2 ​ SO 4 ​ 0,1 M ( K b ​ NH 3 ​ = 1 0 − 5 )

Hitunglah pH dari larutan penyangga berikut ini!

e. 100 mL larutan  0,3 M + 100 mL larutan  0,1 M  space space space

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N. Agnia

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

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Jawaban

pH larutan buffer yang terbentuk adalah 8 + log 5.

pH larutan buffer yang terbentuk adalah 8 + log 5.space space space

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Pembahasan

Pertama kita buat reaksi MRS antara100 mL larutan 0,3M dengan 100 mL larutan 0,1 M. Jadi, pH larutan buffer yang terbentuk adalah 8 + log 5.

Pertama kita buat reaksi MRS antara 100 mL larutan N H subscript 3 0,3 M dengan 100 mL larutan H subscript 2 S O subscript 4 0,1 M.

space space space space space space space space space space space 2 N H subscript 3 space space space space space space space plus space space space space space space space space H subscript 2 S O subscript 4 space space space space space space rightwards arrow space space space space space space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 space space space space space 0 comma 3 space M cross times 100 space mL space space space 0 comma 1 space M cross times 100 space mL M space space space space space 30 space mmol space space space space space space space space space space space space space space 10 space mmol space space space space space space space space space space space space space space space space space space space space space space space minus sign bottom enclose R space space minus sign 20 space mmol space space space space space space space space space space space minus sign 10 space mmol space space space space space space space space space space space space space space plus 10 space mmol end enclose S space space space space space space 10 space mmol space space space space space space space space space space space space space space space space space space space minus sign space space space space space space space space space space space space space space space space space space space space space space space 10 space mmol  


open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end subscript equilibrium space space space 2 N H subscript 4 to the power of plus sign space space plus space space S O subscript 4 to the power of 2 minus sign space space 10 space mmol space space space space space space 20 space mmol space space space space 10 space mmol  open square brackets O H to the power of minus sign close square brackets double bond K subscript b cross times fraction numerator n space N H subscript 3 over denominator n space ion space N H subscript 4 to the power of plus sign end fraction open square brackets O H to the power of minus sign close square brackets equals 10 to the power of negative sign 5 end exponent cross times fraction numerator 10 space mmol over denominator 20 space mmol end fraction open square brackets O H to the power of minus sign close square brackets equals 5 cross times 10 to the power of negative sign 6 end exponent space M   pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets pOH equals minus sign log space left parenthesis 5 cross times 10 to the power of negative sign 6 end exponent right parenthesis pOH equals 6 minus sign log space 5   pH equals 14 minus sign pOH pH equals 14 minus sign left parenthesis 6 minus sign log space 5 right parenthesis pH equals 8 plus log space 5    


Jadi, pH larutan buffer yang terbentuk adalah 8 + log 5.space space space

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