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Pertanyaan

Hitunglah pH campuran larutan 100 mL NH 4 ​ OH 0,1 M dan 100 mL NaOH 0,1 M jika diketahui K b ​ NH 4 ​ OH = 1 × 1 0 − 5 .

Hitunglah pH campuran larutan 100 mL  0,1 M dan 100 mL  0,1 M jika diketahui .

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Jawaban terverifikasi

Jawaban

pH campuran tersebut sebesar 12 + log 5,05.

pH campuran tersebut sebesar 12 + log 5,05.

Pembahasan

Hitung konsentrasi hidroksida dari masing-masing basa terlebih dahulu, kemudian hitung konsentrasi hidroksida campurannya. Jadi, pH campuran tersebut sebesar 12 + log 5,05.

Hitung konsentrasi hidroksida dari masing-masing basa terlebih dahulu, kemudian hitung konsentrasi hidroksida campurannya.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets space dari space N H subscript 4 O H end cell equals cell square root of K subscript b cross times M end root end cell row blank equals cell square root of 1 cross times 10 to the power of negative sign 5 end exponent cross times 0 comma 1 end root end cell row blank equals cell square root of 10 to the power of negative sign 6 end exponent end root end cell row blank equals cell 10 to the power of negative sign 3 end exponent space M end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets space dari space Na O H end cell equals cell b cross times M end cell row blank equals cell 1 cross times 10 to the power of negative sign 1 end exponent end cell row blank equals cell 10 to the power of negative sign 1 end exponent space M end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets space campuran end cell equals cell fraction numerator left parenthesis V cross times open square brackets O H to the power of minus sign close square brackets space dari space N H subscript 4 O H right parenthesis plus left parenthesis V cross times open square brackets O H to the power of minus sign close square brackets space dari space Na O H right parenthesis over denominator V space total end fraction end cell row blank equals cell fraction numerator left parenthesis 100 space mL cross times 10 to the power of negative sign 3 end exponent space M right parenthesis plus left parenthesis 100 space mL cross times 10 to the power of negative sign 1 end exponent space M right parenthesis over denominator 100 space mL plus 100 space mL end fraction end cell row blank equals cell fraction numerator 0 comma 1 space mmol plus 10 space mmol over denominator 200 space mL end fraction end cell row blank equals cell 0 comma 0505 space M end cell row blank equals cell 5 comma 05 cross times 10 to the power of negative sign 2 end exponent space M end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell negative sign log space left parenthesis 5 comma 05 cross times 10 to the power of negative sign 2 end exponent right parenthesis end cell row blank equals cell 2 minus sign log space 5 comma 05 end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell pH space end cell equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign left parenthesis 2 minus sign log space 5 comma 05 right parenthesis end cell row blank equals cell 12 plus log space 5 comma 05 end cell end table end style 


Jadi, pH campuran tersebut sebesar 12 + log 5,05.

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