Roboguru

Hitunglah pH campuran berikut ! 50 mL larutan CH3...

Hitunglah pH campuran berikut !

50 mL larutan CH3COOH 0,2 M dengan 50 mL larutan Ca(OH)2 0,1 M (Ka = 10-5)space

Jawaban:

menentukan mol masing masing :

n space C H subscript 3 C O O H double bond M cross times V space space space space space space space space space space space space space space space space equals 0 comma 2 space cross times space 50 space space space space space space space space space space space space space space space space equals 10 space mmol 

n space Ca open parentheses O H close parentheses subscript 2 equals M space cross times space V space space space space space space space space space space space space space equals 0 comma 1 space cross times 50 space space space space space space space space space space space space space equals 5 space mmol 
menentukan mol garam basa yang terbentuk:

menentukan konsentrasi garam :

Ca open parentheses C H subscript 3 C O O close parentheses subscript 2 yields Ca to the power of 2 plus sign plus 2 space C H subscript 3 C O O to the power of minus sign space space space space space 5 space mmol space space space space space 5 space mmol space space space space 10 space mmol 

V space total space equals space 50 plus 50 space equals 100 space mL open square brackets C H subscript 3 C O O to the power of minus sign close square brackets equals fraction numerator n over denominator v space total end fraction open square brackets C H subscript 3 C O O to the power of minus sign close square brackets equals fraction numerator 10 space mmol over denominator 100 end fraction open square brackets C H subscript 3 C O O to the power of minus sign close square brackets equals 0 comma 1 M 

menentukan [OH-]:

open square brackets O H to the power of minus sign close square brackets equals fraction numerator square root of K subscript w end root over denominator K subscript a end fraction cross times left square bracket anion space garam right square bracket open square brackets O H to the power of minus sign close square brackets equals fraction numerator square root of 10 to the power of negative sign 14 end exponent end root over denominator 10 to the power of negative sign 5 end exponent end fraction cross times left square bracket 0 comma 1 right square bracket open square brackets O H to the power of minus sign close square brackets equals fraction numerator square root of 10 to the power of negative sign 15 end exponent end root over denominator 10 to the power of negative sign 5 end exponent end fraction open square brackets O H to the power of minus sign close square brackets equals square root of 10 to the power of negative sign 10 end exponent end root open square brackets O H to the power of minus sign close square brackets equals 10 to the power of negative sign 5 end exponent

menentukan pH campuran :

pOH space equals space minus sign log space open square brackets O H to the power of minus sign close square brackets pOH space equals space minus sign log space left square bracket 10 to the power of negative sign 5 end exponent right square bracket pOH space equals space 5  pH equals 14 minus sign open parentheses pOH close parentheses pH space equals space 14 minus sign 5 pH space equals space 9 

Jadi, pH campuran yang terbentuk adalah 9.

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved