Hitunglah pH asam flourida 0,5 M. Jika diketahui Ka​=6,6×10−4

Pertanyaan

Hitunglah pH asam flourida 0,5 M. Jika diketahui K subscript a equals 6 comma 6 cross times 10 to the power of negative sign 4 end exponent

N. Puspita

Master Teacher

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Jawaban

pH asam flourida adalah 2- log 1,82

Pembahasan

Pembahasan

Asam flourida begin mathsize 14px style open parentheses H F close parentheses end style termasuk asam lemah. Untuk menghitung pH nya digunakan rumus :

 

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a cross times M end root end cell row cell space space space space space space space space end cell equals cell square root of 6 comma 6 cross times 10 to the power of negative sign 4 end exponent cross times 0 comma 5 end root end cell row cell space space space space space space space space end cell equals cell 1 comma 82 cross times 10 to the power of negative sign 2 end exponent end cell row blank blank blank row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell space space space space space end cell equals cell negative sign log space 1 comma 82 cross times 10 to the power of negative sign 2 end exponent end cell row cell space space space space space end cell equals cell 2 minus sign log space 1 comma 82 end cell end table

Jadi, pH asam flourida adalah 2- log 1,82

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