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Hitunglah kapasitansi pengganti pada rangkaian ter...

begin mathsize 14px style C subscript 1 equals C subscript 2 equals C subscript 3 equals C subscript 4 equals C subscript 5 equals 1 space straight F end style

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Jawaban:

begin mathsize 14px style C subscript p subscript 1 end subscript equals C subscript 3 plus C subscript 4 equals 1 plus 1 equals 2  1 over C subscript s subscript 1 end subscript equals 1 over C subscript p subscript 1 end subscript plus 1 over C subscript 5 1 over C subscript s subscript 1 end subscript equals 1 half plus 1 over 1 1 over C subscript s subscript 1 end subscript equals 3 over 2 C subscript s subscript 1 end subscript equals 2 over 3  C subscript p subscript 2 end subscript equals C subscript s subscript 1 end subscript plus C subscript 2 equals 2 over 3 plus 1 equals 5 over 3  1 over C subscript t o t end subscript equals 1 over C subscript p subscript 2 end subscript plus 1 over C subscript 1 1 over C subscript t o t end subscript equals fraction numerator 1 over denominator begin display style bevelled 5 over 3 end style end fraction plus 1 over 1 1 over C subscript t o t end subscript equals fraction numerator 3 over denominator begin display style 5 end style end fraction plus 1 over 1 1 over C subscript t o t end subscript equals fraction numerator 8 over denominator begin display style 5 end style end fraction C subscript t o t end subscript equals 5 over 8 equals 0 comma 625 space straight F end style  

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