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Hitung konsentrasi ion  dalam larutan  0,01 M jika .

Pertanyaan

Hitung konsentrasi ion H to the power of plus sign dalam larutan N H subscript 3 0,01 M jika K subscript b space N H subscript 3 equals 1 cross times 10 to the power of negative sign 5 end exponentspace

Pembahasan Soal:

Larutan N H subscript 3 merupakan basa lemah, untuk mengetahui konsentrasi ion H to the power of plus sign maka perlu ditentukan dulu konsentrasi ion O H to the power of minus sign nya, yaitu :


table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of K subscript b middle dot M end root end cell row blank equals cell square root of 1 cross times 10 to the power of negative sign 5 end exponent middle dot 0 comma 01 end root end cell row blank equals cell square root of 1 cross times 10 to the power of negative sign 7 end exponent end root end cell row blank equals cell 10 to the power of negative sign 3 comma 5 end exponent space M end cell end table


Dalam suhu ruang nilai tetapan kesetimbangan air (K subscript w) adalah 10 to the power of negative sign 14 end exponent, maka konsentrasi ion H to the power of plus sign dapat ditentukan melalui persamaan berikut.


table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets middle dot open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript w end cell row cell open square brackets H to the power of plus sign close square brackets middle dot open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 14 end exponent end cell row cell open square brackets H to the power of plus sign close square brackets middle dot 10 to the power of negative sign 3 comma 5 end exponent end cell equals cell 10 to the power of negative sign 14 end exponent end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 3 comma 5 end exponent end cell row blank equals cell 10 to the power of negative sign 10 comma 5 end exponent space M end cell end table


Jadi, konsentrasi ion H to the power of plus sign dalam larutan N H subscript 3 tersebut adalah 10 to the power of negative sign 10 comma 5 end exponent space M.space 

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

S. Susanti

Mahasiswa/Alumni Universitas Jayabaya

Terakhir diupdate 30 April 2021

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Asam sulfat 0,1 M merupakan asam kuat dan mengalami ionisasi sebagai berikut:

begin mathsize 14px style H subscript 2 S O subscript 4 yields 2 H to the power of plus sign and S O subscript 4 to the power of 2 minus sign end style 

maka konsentrasi ion hidrogen dan ion hidroksi yang dihasilkan:

Error converting from MathML to accessible text.   

Jadi, konsentrasi Error converting from MathML to accessible text.  

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Pembahasan Soal:

Barium hidroksida merupakan basa kuat yang mengalami ionisasi sempurna sesuai dengan persamaan berikut :

begin mathsize 14px style Ba open parentheses O H close parentheses subscript 2 yields Ba to the power of 2 plus sign and 2 O H to the power of minus sign end style 

Maka, konsentrasi ion hidroksida yang dihasilkan adalah:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open square brackets O H to the power of minus sign close square brackets end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator koefisien space O H to the power of minus sign over denominator koefisien space Ba open parentheses O H close parentheses subscript 2 end fraction cross times left square bracket Ba open parentheses O H close parentheses subscript 2 right square bracket end cell end table table attributes columnalign right center left columnspacing 0px end attributes row cell space space space space space space space space space space end cell equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 2 over 1 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cross times end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 5 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cross times end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 10 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank to the power of negative sign 4 end exponent end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank M end table space space space space space space space space space space equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank 1 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cross times end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 10 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank to the power of negative sign 3 end exponent end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank M end table end style  

Mencari konsentrasi ion hidrogen dari konsentrasi ion hidroksida :

begin mathsize 14px style Kw space space space space space equals open square brackets H to the power of plus sign close square brackets space open square brackets O H to the power of minus sign close square brackets 10 to the power of negative sign 14 end exponent equals open square brackets H to the power of plus sign close square brackets space 1 cross times 10 to the power of negative sign 3 end exponent space open square brackets H to the power of plus sign close square brackets space space equals 1 cross times 10 to the power of negative sign 11 end exponent end style 

Jadi,begin mathsize 14px style space open square brackets O H to the power of minus sign close square brackets equals 1 cross times 10 to the power of negative sign 3 end exponent space M end style dan begin mathsize 14px style open square brackets H to the power of plus sign close square brackets space equals 1 space cross times 10 to the power of negative sign 11 end exponent end style 

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Tentukan  dan  dalam larutan yang nilai pH-nya: 4,3 (diketahui log 5 = 0,7)

Pembahasan Soal:

Besarnya konsentrasi ion open square brackets H to the power of plus sign close square brackets dapat ditentukan dengan cara sebagai berikut.


table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell 4 comma 3 end cell equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell left parenthesis 5 minus sign 0 comma 7 right parenthesis end cell equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell negative sign antilog left parenthesis 5 minus sign 0 comma 7 right parenthesis end cell row blank equals cell negative sign antilog left parenthesis 5 minus sign log space 5 right parenthesis end cell row blank equals cell 10 to the power of negative sign 5 end exponent cross times 5 end cell row blank equals cell 5 cross times 10 to the power of negative sign 5 end exponent space M end cell end table


Sementara konsentrasi ion open square brackets O H to the power of minus sign close square brackets dalam larutan tersebut yaitu :


table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript w end cell equals cell 10 to the power of negative sign 14 end exponent end cell row blank blank blank row cell open square brackets H to the power of plus sign close square brackets middle dot open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript w end cell row cell left parenthesis 5 cross times 10 to the power of negative sign 5 end exponent right parenthesis middle dot open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 14 end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell fraction numerator 10 to the power of negative sign 14 end exponent over denominator 5 cross times 10 to the power of negative sign 5 end exponent end fraction end cell row blank equals cell 0 comma 2 cross times 10 to the power of negative sign 9 end exponent end cell row blank equals cell 2 cross times 10 to the power of negative sign 10 end exponent space M end cell end table


Jadi, open square brackets H to the power of plus sign close square brackets dan open square brackets O H to the power of minus sign close square brackets dalam larutan tersebut secara berturut-turut yaitu 5 cross times 10 to the power of negative sign 5 end exponent space M dan 2 cross times 10 to the power of negative sign 10 end exponent space M.space 

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Tentukan  dan  dalam larutan yang nilai pH-nya: 2,125 (gunakan kalkulator)

Pembahasan Soal:

Hubungan konsentrasi ion H to the power of plus sign dengan pH dapat dituliskan dalam persamaan berikut.


table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row blank blank cell maka comma end cell row cell 2 comma 125 end cell equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell negative sign antilog space 2 comma 125 end cell row blank equals cell 7 comma 5 cross times 10 to the power of negative sign 3 end exponent space M end cell end table


Sementara nilai open square brackets O H to the power of minus sign close square brackets dalam larutan tersebut dapat ditentukan dengan cara berikut.


table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript w end cell equals cell 10 to the power of negative sign 14 end exponent end cell row blank blank blank row cell open square brackets H to the power of plus sign close square brackets middle dot open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript w end cell row cell left parenthesis 7 comma 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis middle dot open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 14 end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell fraction numerator 10 to the power of negative sign 14 end exponent over denominator 7 comma 5 cross times 10 to the power of negative sign 3 end exponent end fraction end cell row blank equals cell 0 comma 13 cross times 10 to the power of negative sign 11 end exponent end cell row blank equals cell 1 comma 3 cross times 10 to the power of negative sign 12 end exponent space M end cell end table


Jadi, open square brackets H to the power of plus sign close square brackets dan open square brackets O H to the power of minus sign close square brackets dalam larutan tersebut secara berturut-turut adalah 7 comma 5 cross times 10 to the power of negative sign 3 end exponent space M dan 1 comma 3 cross times 10 to the power of negative sign 12 end exponent space M.space 

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Berapakah konsentrasi ion  dalam larutan jika konsentrasi  (Diketahui ) ....

Pembahasan Soal:

Penentuan konsentrasi undefined dapat dihitung dari rumus hubungan antara undefinedbegin mathsize 14px style open square brackets O H to the power of minus sign close square brackets end style, dengan begin mathsize 14px style K subscript italic w end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript italic w end cell equals cell open square brackets H to the power of plus sign close square brackets cross times open square brackets O H to the power of minus sign close square brackets end cell row cell 10 to the power of negative sign 14 end exponent end cell equals cell 2 cross times 10 to the power of negative sign 4 end exponent space cross times open square brackets O H to the power of minus sign close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell fraction numerator 10 to the power of negative sign 14 end exponent over denominator 2 cross times 10 to the power of negative sign 4 end exponent space end fraction end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 5 cross times 10 to the power of negative sign 11 end exponent space end cell end table end style   

Jadi, begin mathsize 14px style open square brackets O H to the power of minus sign close square brackets end style dalam larutan adalah begin mathsize 14px style 5 cross times 10 to the power of negative sign 11 end exponent end style.

0

Roboguru

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