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Himpunan penyelesaian dari pertidaksamaan x − 1 1 ​ + x 1 ​ + x + 1 1 ​ > 0 adalah ....

Himpunan penyelesaian dari pertidaksamaan  adalah ....

  1. begin mathsize 14px style open curly brackets x vertical line x less than negative 1 text  atau  end text minus 1 third less than x less than 1 third text  atau  end text x greater than 1 comma x element of straight real numbers close curly brackets end style    

  2. begin mathsize 14px style open curly brackets x vertical line x less than negative 1 text  atau  end text minus 1 third less than x less than 0 text  atau  end text 1 third less than x less than 1 comma x element of straight real numbers close curly brackets end style    

  3. begin mathsize 14px style open curly brackets x vertical line negative 1 less than x less than negative 1 third text  atau  end text 0 less than x less than 1 third text  atau  end text x greater than 1 comma x element of straight real numbers close curly brackets end style    

  4. begin mathsize 14px style open curly brackets x vertical line x less than negative 1 text  atau  end text minus 1 third square root of 3 less than x less than 0 text  atau  end text 1 third square root of 3 less than x less than 1 comma x element of straight real numbers close curly brackets end style    

  5. begin mathsize 14px style open curly brackets x vertical line negative 1 less than x less than negative 1 third square root of 3 text  atau  end text 0 less than x less than 1 third square root of 3 text  atau  end text x greater than 1 comma x element of straight real numbers close curly brackets end style    

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

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Pembahasan

Perhatikan bahwa Sehingga didapat pembuat nol dari pembilang pada bentuk rasionalnya yaitu atau ,dan dari penyebutnya yaitu x = 1 , x = 0 , atau x = -1 . Dengan menggunakan garis bilangan, didapat Sehingga didapat himpunan penyelesaian dari pertidaksamaan tersebut yaitu

Perhatikan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 over denominator x minus 1 end fraction plus 1 over x plus fraction numerator 1 over denominator x plus 1 end fraction end cell greater than 0 row cell fraction numerator x open parentheses x plus 1 close parentheses over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction plus fraction numerator open parentheses x minus 1 close parentheses open parentheses x plus 1 close parentheses over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction plus fraction numerator open parentheses x minus 1 close parentheses x over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction end cell greater than 0 row cell fraction numerator x squared plus x over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction plus fraction numerator x squared minus 1 over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction plus fraction numerator x squared minus x over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction end cell greater than 0 row cell fraction numerator open parentheses x squared plus x close parentheses plus open parentheses x squared minus 1 close parentheses plus open parentheses x squared minus x close parentheses over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction end cell greater than 0 row cell fraction numerator 3 x squared minus 1 over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction end cell greater than 0 row cell fraction numerator open parentheses x square root of 3 minus 1 close parentheses open parentheses x square root of 3 plus 1 close parentheses over denominator open parentheses x minus 1 close parentheses x open parentheses x plus 1 close parentheses end fraction end cell greater than 0 end table end style

Sehingga didapat pembuat nol dari pembilang pada bentuk rasionalnya yaitu begin mathsize 14px style x equals fraction numerator 1 over denominator square root of 3 end fraction equals 1 third square root of 3 end style atau begin mathsize 14px style x equals negative fraction numerator 1 over denominator square root of 3 end fraction equals 1 third square root of 3 end style, dan dari penyebutnya yaitu = 1, = 0, atau = -1.

Dengan menggunakan garis bilangan, didapat

Sehingga didapat himpunan penyelesaian dari pertidaksamaan tersebut yaitu

begin mathsize 14px style open curly brackets x vertical line negative 1 less than x less than negative 1 third square root of 3 text  atau  end text 0 less than x less than 1 third square root of 3 text  atau  end text x greater than 1 comma x element of straight real numbers close curly brackets end style    

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Penyelesaian dari pertidaksamaan x − 2 x − 1 ​ < 0 adalah ....

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