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Pertanyaan

Himpunan penyelesaian dari adalah ....

Himpunan penyelesaian dari begin mathsize 14px style 2 open parentheses 2 x minus 3 close parentheses plus 3 open parentheses 4 minus x close parentheses plus 2 x minus 1 greater than x minus 10 minus open parentheses x minus 4 close parentheses plus 3 open parentheses 2 x plus 4 close parentheses end style adalah ....

  1. begin mathsize 14px style open curly brackets x vertical line x less than 3 comma space x element of straight real numbers close curly brackets end style 

  2. begin mathsize 14px style open curly brackets straight x vertical line straight x greater than 1 third comma space straight x space element of space straight real numbers close curly brackets end style 

  3. begin mathsize 14px style open curly brackets straight x vertical line straight x less than 1 third comma space straight x space element of space straight real numbers close curly brackets end style 

  4. begin mathsize 14px style open curly brackets straight x vertical line straight x greater than negative 1 third comma space straight x space element of space straight real numbers close curly brackets end style 

  5. begin mathsize 14px style open curly brackets straight x vertical line straight x less than negative 1 third comma space straight x space element of space straight real numbers close curly brackets end style 

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

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Pembahasan

Maka himpunan penyelesaian pertidaksamaan tersebut adalah . Jadi, jawaban yang tepat adalah E.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 2 open parentheses 2 straight x minus 3 close parentheses plus 3 open parentheses 4 minus straight x close parentheses plus 2 straight x minus 1 end cell greater than cell straight x minus 10 minus open parentheses straight x minus 4 close parentheses plus 3 open parentheses 2 straight x plus 4 close parentheses end cell row cell 4 straight x minus 6 plus 12 minus 3 straight x plus 2 straight x minus 1 end cell greater than cell straight x minus 10 minus straight x plus 4 plus 6 straight x plus 12 end cell row cell 3 straight x plus 5 end cell greater than cell 6 straight x plus 6 end cell row cell negative 3 straight x end cell greater than 1 row cell fraction numerator negative 3 straight x over denominator negative 3 end fraction end cell less than cell fraction numerator 1 over denominator negative 3 end fraction end cell row straight x less than cell negative 1 third end cell row blank blank blank end table end style  

Maka himpunan penyelesaian pertidaksamaan tersebut adalah begin mathsize 14px style open curly brackets straight x vertical line straight x less than negative 1 third comma space straight x space element of space straight real numbers close curly brackets end style.

Jadi, jawaban yang tepat adalah E.

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