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Hasil kali akar-akar persamaan ( 25 1 ​ ) − x 2 + x − 1 = 12 5 x 2 + 2 x + 3 adalah..

Hasil kali akar-akar persamaan  adalah..

  1. 15

  2. 8

  3. 7

  4. negative 7

  5. negative 8

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N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C

jawaban yang tepat adalah C

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Pembahasan

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Ingat kembali: Jika Pertama kita ubah: Sehingga diperoleh perhitungan: Maka, Jumlah akar-akar persamaan tersebut: Dengan demikian, asil kali akar-akar persamaan adalah Jadi, jawaban yang tepat adalah C

Ingat kembali:

a to the power of n equals stack stack a cross times a cross times a cross times... cross times a with underbrace below with a space s e b a n y a k space n below comma space a not equal to 0 

1 over a to the power of n equals a to the power of negative n end exponent comma space a not equal to 0 

open parentheses a to the power of m close parentheses to the power of n equals a to the power of m times n end exponent comma space a not equal to 0 

a to the power of f open parentheses x close parentheses end exponent equals a to the power of g open parentheses x close parentheses end exponent rightwards arrow f open parentheses x close parentheses equals g open parentheses x close parentheses

Jika  f open parentheses x close parentheses equals a x squared plus b x plus c comma space maka space x subscript 1 times x subscript 2 equals c over a

Pertama kita ubah:

25 equals 5 cross times 5 equals 5 squared

125 equals 5 cross times 5 cross times 5 equals 5 cubed

Sehingga diperoleh perhitungan:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 1 over 25 close parentheses to the power of negative x squared plus x minus 1 end exponent end cell equals cell 125 to the power of x squared plus 2 x plus 3 end exponent end cell row cell open parentheses 1 over 5 squared close parentheses to the power of negative x squared plus x minus 1 end exponent end cell equals cell open parentheses 5 cubed close parentheses to the power of x squared plus 2 x plus 3 end exponent end cell row cell open parentheses 5 to the power of negative 2 end exponent close parentheses to the power of negative x squared plus x minus 1 end exponent end cell equals cell 5 cubed to the power of open parentheses x squared plus 2 x plus 3 close parentheses end exponent end cell row cell 5 to the power of negative 2 end exponent to the power of open parentheses negative x squared plus x minus 1 close parentheses end exponent end cell equals cell 5 to the power of 3 x squared plus 6 x plus 9 end exponent end cell row cell 5 to the power of 2 x squared minus 2 x plus 2 end exponent end cell equals cell 5 to the power of 3 x squared plus 6 x plus 9 end exponent comma space sehingga end cell row cell 2 straight x squared minus 2 straight x plus 2 end cell equals cell 3 straight x squared plus 6 straight x plus 9 end cell row cell 2 straight x squared minus 2 straight x plus 2 minus 3 straight x squared minus 6 straight x minus 9 end cell equals 0 row cell negative straight x squared plus 4 straight x minus 7 end cell equals 0 row blank blank cell straight a equals negative 1 comma space straight b equals 4 space straight c equals negative 7 end cell end table   

Maka, Jumlah akar-akar persamaan tersebut:

table attributes columnalign right center left columnspacing 0px end attributes row cell x subscript 1 times x subscript 2 end cell equals cell c over a end cell row blank equals cell fraction numerator open parentheses negative 7 close parentheses over denominator open parentheses negative 1 close parentheses end fraction end cell row blank equals 7 end table  

Dengan demikian, asil kali akar-akar persamaan open parentheses 1 over 25 close parentheses to the power of negative x squared plus x minus 1 end exponent equals 125 to the power of x squared plus 2 x plus 3 end exponent adalah 7

Jadi, jawaban yang tepat adalah C

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