Pertanyaan

Hasil dari

Hasil dari $begin mathsize 14px style integral open parentheses 6 sin invisible function application 3 x plus fraction numerator 1 over denominator 2 x to the power of 4 end fraction close parentheses d x equals... end style$

$begin mathsize 14px style 18 cos invisible function application 3 x minus fraction numerator 1 over denominator 2 x cubed end fraction plus C end style$
$begin mathsize 14px style negative 18 cos invisible function application 3 x plus fraction numerator 1 over denominator 6 x squared end fraction plus C end style$
$begin mathsize 14px style 2 cos invisible function application 3 x minus fraction numerator 1 over denominator 6 x cubed end fraction plus C end style$
$begin mathsize 14px style negative 2 cos invisible function application 3 x plus fraction numerator 1 over denominator 2 x cubed end fraction plus C end style$
$begin mathsize 14px style negative 2 cos invisible function application 3 x minus fraction numerator 1 over denominator 6 x cubed end fraction plus C end style$

A. Khairunisa

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Pembahasan

Ingat kembali salah satu sifat integral berikut ini. Maka,

Ingat kembali salah satu sifat integral berikut ini.

Maka,

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral open parentheses 6 space sin space 3 x plus fraction numerator 1 over denominator 2 x to the power of 4 end fraction close parentheses space d x end cell equals cell integral 6 space sin space 3 x space d x plus integral fraction numerator 1 over denominator 2 x to the power of 4 end fraction d x end cell row blank equals cell 6 integral sin space 3 x space d x plus 1 half integral x to the power of negative 4 end exponent space d x end cell row blank equals cell 6 times open parentheses negative 1 third cos invisible function application 3 x close parentheses plus 1 half times open parentheses fraction numerator 1 over denominator negative 4 plus 1 end fraction x to the power of negative 4 plus 1 end exponent close parentheses plus C end cell row blank equals cell negative 2 cos invisible function application 3 x plus 1 half open parentheses fraction numerator 1 over denominator negative 3 end fraction x to the power of negative 3 end exponent close parentheses plus C end cell row blank equals cell negative 2 cos invisible function application 3 x minus fraction numerator 1 over denominator 6 x cubed end fraction plus C end cell end table end style$