Pertanyaan

Hasil dari ∫ sec x d x = ...

Hasil dari $\int sec x d x = ...$

N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

Agar dapat menggunakan integral subsitusi perlu kita kalikan dengan Sehingga fungsi tersebut menjadi, Kemudian kita gunakan integral substitusi dengan memisalkan u = sec x + tan x sehingga diperoleh, Maka,

Agar dapat menggunakan integral subsitusi perlu kita kalikan dengan

$begin mathsize 14px style fraction numerator sec invisible function application x plus tan invisible function application x over denominator sec invisible function application x plus tan invisible function application x end fraction end style$

Sehingga fungsi tersebut menjadi,

Kemudian kita gunakan integral substitusi dengan memisalkan u=secx+tanx sehingga diperoleh,

$begin mathsize 14px style fraction numerator d u over denominator d x end fraction equals sec invisible function application x plus tan invisible function application x d x equals fraction numerator d u over denominator sec invisible function application x tan invisible function application x plus sec squared invisible function application x end fraction end style$

Maka,

$begin mathsize 14px style integral sec invisible function application x d x equals integral open parentheses sec invisible function application x times fraction numerator sec invisible function application x plus tan invisible function application x over denominator sec invisible function application x plus tan invisible function application x end fraction close parentheses d x space space space space space space space space space space space space space space space space space space space space equals integral open parentheses fraction numerator sec squared invisible function application x plus sec invisible function application x tan invisible function application x over denominator sec invisible function application x plus tan invisible function application x end fraction close parentheses d x space space space space space space space space space space space space space space space space space space space space equals integral open parentheses fraction numerator sec squared invisible function application x plus sec invisible function application x tan invisible function application x over denominator u end fraction close parentheses times fraction numerator d u over denominator sec invisible function application x tan invisible function application x plus sec squared invisible function application x end fraction space space space space space space space space space space space space space space space space space space space space equals integral 1 over u d u space space space space space space space space space space space space space space space space space space space space equals ln invisible function application u plus C space space space space space space space space space space space space space space space space space space space space equals ln invisible function application open vertical bar sec invisible function application x plus tan invisible function application x close vertical bar plus C end style$