Pertanyaan

Hasil dari

Y. Endah

Master Teacher

Mahasiswa/Alumni Institut Teknologi Bandung

Jawaban terverifikasi

Pembahasan

$M i s a l k a n space u equals x cubed minus 7 left right double arrow d u equals 3 x squared d x left right double arrow d x equals fraction numerator d u over denominator 3 x squared end fraction integral x squared open parentheses x cubed minus 7 close parentheses to the power of 5 space d x equals integral x squared space u to the power of 5 space fraction numerator d u over denominator 3 x squared end fraction equals integral u to the power of 5 over 3 d u equals u to the power of 6 over 18 plus C equals 1 over 18 open parentheses x cubed minus 7 close parentheses to the power of 6 plus C$