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Hasil dari integral fraction numerator left parenthesis 6 x minus 2 right parenthesis over denominator left parenthesis 9 x squared minus 6 x plus 12 right parenthesis cubed end fraction d x equals...

Pembahasan Soal:

Dengan menggunakan konsep integral tak tentu, maka misalkan:

table attributes columnalign right center left columnspacing 0px end attributes row u equals cell 9 x squared minus 6 x plus 12 end cell row cell d u end cell equals cell 18 x minus 6 space end cell end table

Selanjutnya,

6 x minus 2 d x equals 1 third d u

Jadi,

table attributes columnalign right center left columnspacing 0px end attributes row cell integral fraction numerator left parenthesis 6 x minus 2 right parenthesis over denominator left parenthesis 9 x squared minus 6 x plus 12 right parenthesis cubed end fraction d x end cell equals cell integral left parenthesis 6 x minus 2 right parenthesis left parenthesis 9 x squared minus 6 x plus 12 right parenthesis to the power of negative 3 end exponent d x end cell row blank equals cell integral 1 third u to the power of negative 3 end exponent d u end cell row blank equals cell fraction numerator 1 over denominator 3 cross times left parenthesis negative 2 right parenthesis end fraction u to the power of negative 2 end exponent plus c end cell row blank equals cell fraction numerator 1 over denominator negative 6 end fraction u to the power of negative 2 end exponent plus c end cell row blank equals cell fraction numerator 1 over denominator negative 6 end fraction open parentheses 9 x squared minus 6 x plus 12 close parentheses to the power of negative 2 end exponent plus c end cell end table

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 Juni 2021

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