Pertanyaan

Hasil dari x → 0 lim sinxcosx 4 x + 3 xcos 2 x adalah ....

Hasil dari $x \to 0 lim \frac{4 x + 3 xcos 2 x}{sinxcosx}$ adalah ....

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

K. Putri

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Ganesha

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Perhatikan perhitungan berikut! Dengan demikian, hasil dari adalah 7. Jadi, jawaban yang tepat adalah B.

Perhatikan perhitungan berikut!

$begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as straight x rightwards arrow 0 of invisible function application fraction numerator 4 straight x plus 3 xcos invisible function application 2 straight x over denominator sin invisible function application xcos invisible function application straight x end fraction end cell row blank equals cell limit as straight x rightwards arrow 0 of invisible function application open parentheses fraction numerator 4 straight x over denominator sin invisible function application xcos invisible function application straight x end fraction plus fraction numerator 3 xcos invisible function application 2 straight x over denominator sin invisible function application xcos invisible function application straight x end fraction close parentheses end cell row blank equals cell limit as straight x rightwards arrow 0 of invisible function application fraction numerator 4 straight x over denominator sin invisible function application xcos invisible function application straight x end fraction plus limit as straight x rightwards arrow 0 of invisible function application fraction numerator 3 xcos invisible function application 2 straight x over denominator sin invisible function application xcos invisible function application straight x end fraction end cell row blank equals cell limit as straight x rightwards arrow 0 of invisible function application fraction numerator straight x over denominator sin invisible function application straight x end fraction times limit as straight x rightwards arrow 0 of invisible function application fraction numerator 4 over denominator cos invisible function application straight x end fraction plus limit as straight x rightwards arrow 0 of invisible function application fraction numerator straight x over denominator sin invisible function application straight x end fraction times limit as straight x rightwards arrow 0 of invisible function application fraction numerator 3 cos invisible function application 2 straight x over denominator cos invisible function application straight x end fraction end cell row blank equals cell 1 times fraction numerator 4 over denominator cos invisible function application 0 end fraction plus 1 times fraction numerator 3 cos invisible function application 2 left parenthesis 0 right parenthesis over denominator cos invisible function application 0 end fraction end cell row blank equals cell 1 times 4 over 1 plus 1 times fraction numerator 3 times 1 over denominator 1 end fraction end cell row blank equals cell 4 plus 3 end cell row blank equals 7 end table end style$

Dengan demikian, hasil dari $begin mathsize 14px style limit as straight x rightwards arrow 0 of fraction numerator 4 straight x plus 3 xcos 2 straight x over denominator sinxcosx end fraction end style$ adalah 7.

Jadi, jawaban yang tepat adalah B.