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Pertanyaan

Hasil dari adalah ...

Hasil dari begin mathsize 14px style limit as x rightwards arrow negative straight infinity of invisible function application fraction numerator open parentheses 5 x minus 6 close parentheses times open parentheses 2 x plus 1 close parentheses cubed over denominator open parentheses 10 x cubed minus 5 close parentheses times square root of 16 x squared minus 5 x end root end fraction end style  adalah ...

  1. - ∞
     

  2. -1

  3. 0

  4. 1

     

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Jawaban terverifikasi

Jawaban

jawaban yang tepatadalah B.

jawaban yang tepat adalah B.

Pembahasan

Misalkan x = - p sehingga p = - x , maka apabila x → -∞ , didapat bahwa p → ∞ . Sehingga Jadi, jawaban yang tepatadalah B.

Misalkan x = -p  sehingga p = -x , maka apabila x → -∞ , didapat bahwa p → ∞ . Sehingga

begin mathsize 14px style limit as x rightwards arrow negative straight infinity of invisible function application fraction numerator open parentheses 5 x minus 6 close parentheses times open parentheses 2 x plus 1 close parentheses cubed over denominator open parentheses 10 x cubed minus 5 close parentheses times square root of 16 x squared minus 5 x end root end fraction equals limit as p rightwards arrow straight infinity of invisible function application fraction numerator open parentheses 5 open parentheses negative p close parentheses minus 6 close parentheses times open parentheses 2 open parentheses negative p close parentheses plus 1 close parentheses cubed over denominator open parentheses 10 open parentheses negative p close parentheses cubed minus 5 close parentheses times square root of 16 open parentheses negative p close parentheses squared minus 5 open parentheses negative p close parentheses end root end fraction equals limit as p rightwards arrow straight infinity of invisible function application fraction numerator open parentheses negative 5 p minus 6 close parentheses times open parentheses negative 2 p plus 1 close parentheses cubed over denominator open parentheses negative 10 p cubed minus 5 close parentheses times square root of 16 p squared plus 5 p end root end fraction equals limit as p rightwards arrow straight infinity of invisible function application fraction numerator open parentheses negative 5 p minus 6 close parentheses open parentheses negative 2 p plus 1 close parentheses cubed over denominator open parentheses negative 10 p cubed minus 5 close parentheses times square root of 16 p squared plus 5 p end root end fraction times fraction numerator 1 over p to the power of 4 over denominator 1 over p to the power of 4 end fraction equals limit as p rightwards arrow straight infinity of invisible function application fraction numerator open parentheses negative 5 p minus 6 close parentheses times open parentheses negative 2 p plus 1 close parentheses cubed over denominator open parentheses negative 10 p cubed minus 5 close parentheses times square root of 16 p squared plus 5 p end root end fraction times fraction numerator 1 over p times 1 over p cubed over denominator 1 over p cubed times 1 over p end fraction equals limit as p rightwards arrow straight infinity of invisible function application fraction numerator open parentheses negative 5 p minus 6 close parentheses times open parentheses negative 2 p plus 1 close parentheses cubed over denominator open parentheses negative 10 p cubed minus 5 close parentheses times square root of 16 p squared plus 5 p end root end fraction times fraction numerator 1 over p times open parentheses 1 over p close parentheses cubed over denominator 1 over p cubed times square root of 1 over p squared end root end fraction equals limit as p rightwards arrow straight infinity of invisible function application fraction numerator open parentheses negative 5 p minus 6 close parentheses times 1 over p times open parentheses negative 2 p plus 1 close parentheses cubed times open parentheses 1 over p close parentheses cubed over denominator open parentheses negative 10 p cubed minus 5 close parentheses times 1 over p cubed times square root of 16 p squared plus 5 p end root times square root of 1 over p squared end root end fraction equals limit as p rightwards arrow straight infinity of invisible function application fraction numerator open parentheses negative 5 p minus 6 close parentheses times 1 over p times open parentheses open parentheses negative 2 p plus 1 close parentheses times 1 over p close parentheses cubed over denominator open parentheses negative 10 p cubed minus 5 close parentheses times 1 over p cubed times square root of open parentheses 16 p squared plus 5 p close parentheses times 1 over p squared end root end fraction equals limit as p rightwards arrow straight infinity of invisible function application fraction numerator open parentheses negative 5 minus 6 over p close parentheses times open parentheses negative 2 plus 1 over p close parentheses cubed over denominator open parentheses negative 10 minus 5 over p cubed close parentheses times square root of 16 plus 5 over p end root end fraction equals fraction numerator open parentheses negative 5 minus 0 close parentheses times open parentheses negative 2 plus 0 close parentheses cubed over denominator open parentheses negative 10 minus 0 close parentheses times square root of 16 plus 0 end root end fraction equals fraction numerator open parentheses negative 5 close parentheses times open parentheses negative 2 close parentheses cubed over denominator open parentheses negative 10 close parentheses times square root of 16 end fraction equals fraction numerator open parentheses negative 5 close parentheses times open parentheses negative 8 close parentheses over denominator open parentheses negative 10 close parentheses times 4 end fraction equals fraction numerator 40 over denominator negative 40 end fraction equals negative 1 end style        

Jadi, jawaban yang tepat adalah B.

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