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Hasil dari adalah ....

Hasil dari begin mathsize 14px style integral open parentheses x minus 1 close parentheses open parentheses 2 x plus 5 close parentheses squared blank d x end style adalah ....

  1. begin mathsize 14px style x to the power of 4 plus 16 over 3 x cubed plus 5 over 2 x squared plus 25 x plus C end style 

  2. begin mathsize 14px style x to the power of 4 plus 16 over 3 x cubed plus 5 over 2 x squared minus 25 x plus C end style 

  3. begin mathsize 14px style x to the power of 4 plus 8 x cubed plus 5 over 2 x squared plus 25 x plus C end style 

  4. begin mathsize 14px style x to the power of 4 plus 8 x cubed plus 5 over 2 x squared minus 25 x plus C end style 

  5. begin mathsize 14px style 4 x to the power of 4 plus 8 x cubed plus 5 over 2 x squared minus 25 x plus C end style 

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.

Pembahasan

Perhatikan perhitungan berikut. Misalkan maka Jadi, jawaban yang tepat adalah B.

Perhatikan perhitungan berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral open parentheses x minus 1 close parentheses open parentheses 2 x plus 5 close parentheses squared blank d x end cell equals cell integral open parentheses x minus 1 close parentheses open parentheses 2 x plus 5 close parentheses open parentheses 2 x plus 5 close parentheses blank d x end cell row blank equals cell integral open parentheses 4 x cubed plus 16 x squared plus 5 x minus 25 close parentheses blank d x end cell row blank equals cell integral 4 x cubed blank d x plus integral 16 x squared blank d x plus integral 5 x blank d x minus integral 25 blank d x end cell row blank equals cell 4 integral x cubed blank d x plus 16 integral x squared blank d x plus 5 integral x blank d x minus 25 integral 1 blank d x end cell row blank equals cell 4 open parentheses fraction numerator 1 over denominator 3 plus 1 end fraction x to the power of 3 plus 1 end exponent plus C subscript 1 close parentheses plus 16 open parentheses fraction numerator 1 over denominator 2 plus 1 end fraction x to the power of 2 plus 1 end exponent plus C subscript 2 close parentheses plus 5 open parentheses fraction numerator 1 over denominator 1 plus 1 end fraction x to the power of 1 plus 1 end exponent plus C subscript 3 close parentheses minus 25 open parentheses x plus C subscript 4 close parentheses end cell row blank equals cell 4 times 1 fourth x to the power of 4 plus 4 C subscript 1 plus 16 times 1 third x cubed plus 16 C subscript 2 plus 5 times 1 half x squared plus 5 C subscript 3 minus 25 x minus 25 C subscript 4 end cell row blank equals cell x to the power of 4 plus 16 over 3 x cubed plus 5 over 2 x squared minus 25 x plus 4 C subscript 1 plus 16 C subscript 2 plus 5 C subscript 3 minus 25 C subscript 4 end cell end table end style 

Misalkan begin mathsize 14px style 4 C subscript 1 plus 16 C subscript 2 plus 5 C subscript 3 minus 25 C subscript 4 equals C comma end style maka

begin mathsize 14px style x to the power of 4 plus 16 over 3 x cubed plus 5 over 2 x squared minus 25 x plus 4 C subscript 1 plus 16 C subscript 2 plus 5 C subscript 3 minus 25 C subscript 4 equals x to the power of 4 plus 16 over 3 x cubed plus 5 over 2 x squared minus 25 x plus C end style 

Jadi, jawaban yang tepat adalah B.

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