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Hasil dari 1 6 4 3 ​ 4 × 2 2 1 ​ × 8 6 1 ​ ​ adalah ....

Hasil dari  adalah ....

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N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

hasilnya adalah 1.

hasilnya adalah 1.

Pembahasan

Pembahasan
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Gunakan sifat ekponensial berikut: Perhatikan perhitungan berikut. Jadi, hasilnya adalah 1.

Gunakan sifat ekponensial berikut:

begin mathsize 14px style a to the power of m cross times a to the power of n equals a to the power of m plus n end exponent a to the power of m over a to the power of n equals a to the power of m minus n end exponent open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent end style 

Perhatikan perhitungan berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell fraction numerator 4 cross times 2 to the power of begin display style 1 half end style end exponent cross times 8 to the power of begin display style 1 over 6 end style end exponent over denominator 16 to the power of begin display style 3 over 4 end style end exponent end fraction end cell equals cell fraction numerator 2 squared cross times 2 to the power of begin display style 1 half end style end exponent cross times open parentheses 2 cubed close parentheses to the power of begin display style 1 over 6 end style end exponent over denominator open parentheses 2 to the power of 4 close parentheses to the power of begin display style 3 over 4 end style end exponent end fraction end cell row blank equals cell fraction numerator 2 squared cross times 2 to the power of begin display style 1 half end style end exponent cross times 2 to the power of 3 cross times begin display style 1 over 6 end style end exponent over denominator 2 to the power of 4 cross times begin display style 3 over 4 end style end exponent end fraction end cell row blank equals cell fraction numerator 2 squared cross times 2 to the power of begin display style 1 half end style end exponent cross times 2 to the power of begin display style 1 half end style end exponent over denominator 2 cubed end fraction end cell row blank equals cell 2 to the power of open parentheses 2 plus 1 half plus 1 half minus 3 close parentheses end exponent end cell row blank equals cell 2 to the power of 0 end cell row cell fraction numerator 4 cross times 2 to the power of begin display style 1 half end style end exponent cross times 8 to the power of begin display style 1 over 6 end style end exponent over denominator 16 to the power of begin display style 3 over 4 end style end exponent end fraction end cell equals 1 end table end style  

Jadi, hasilnya adalah 1.

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Jawaban tidak sesuai Pembahasan terpotong Pembahasan tidak menjawab soal Pembahasan tidak lengkap

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