Pertanyaan

Hasil dari adalah ....

R. RGFLSATU

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

Pembahasan

Perhatikan perhitungan berikut. Misalkan maka Jadi, jawaban yang tepat adalah E.

Perhatikan perhitungan berikut.

$begin mathsize 14px style integral open parentheses 19 x to the power of 18 minus 18 x to the power of negative 19 end exponent plus 14 root index 13 of x close parentheses blank d xequals integral 19 x to the power of 18 blank d x minus integral 18 x to the power of negative 19 end exponent blank d x plus integral 14 root index 13 of x blank d xequals 19 integral x to the power of 18 blank d x minus 18 integral x to the power of negative 19 end exponent blank d x plus 14 integral x to the power of 1 over 13 end exponent blank d xequals 19 open parentheses fraction numerator 1 over denominator 18 plus 1 end fraction x to the power of 18 plus 1 end exponent plus C subscript 1 close parentheses minus 18 open parentheses fraction numerator 1 over denominator negative 19 plus 1 end fraction x to the power of negative 19 plus 1 end exponent plus C subscript 2 close parentheses plus 14 open parentheses fraction numerator 1 over denominator 1 over 13 plus 1 end fraction x to the power of 1 over 13 plus 1 end exponent plus C subscript 3 close parenthesesequals 19 open parentheses 1 over 19 x to the power of 19 plus C subscript 1 close parentheses minus 18 open parentheses fraction numerator 1 over denominator negative 18 end fraction x to the power of negative 18 end exponent plus C subscript 2 close parentheses plus 14 open parentheses fraction numerator 1 over denominator 14 over 13 end fraction x to the power of 14 over 13 end exponent plus C subscript 3 close parenthesesequals 19 times 1 over 19 x to the power of 19 plus 19 C subscript 1 minus 18 times fraction numerator 1 over denominator negative 18 end fraction x to the power of negative 18 end exponent minus 18 C subscript 2 plus 14 times 13 over 14 x to the power of 14 over 13 end exponent plus 14 C subscript 3equals x to the power of 19 plus 19 C subscript 1 plus x to the power of negative 18 end exponent minus 18 C subscript 2 plus 13 x to the power of 14 over 13 end exponent plus 14 C subscript 3equals x to the power of 19 plus 1 over x to the power of 18 plus 13 x root index 13 of x plus 19 C subscript 1 minus 18 C subscript 2 plus 14 C subscript 3 end style$

Misalkan maka

begin mathsize 14px style x to the power of 19 plus 1 over x to the power of 18 plus 13 x root index 13 of x plus 19 C subscript 1 minus 18 C subscript 2 plus 14 C subscript 3 equals x to the power of 19 plus 1 over x to the power of 18 plus 13 x root index 13 of x plus C end style

Jadi, jawaban yang tepat adalah E.