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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

Pembahasan

Perhatikan perhitungan berikut. Misalkan maka Jadi, jawaban yang tepat adalah E.

Perhatikan perhitungan berikut.

$begin mathsize 14px style integral open parentheses 19 x to the power of 18 minus 18 x to the power of negative 19 end exponent plus 14 root index 13 of x close parentheses blank d xequals integral 19 x to the power of 18 blank d x minus integral 18 x to the power of negative 19 end exponent blank d x plus integral 14 root index 13 of x blank d xequals 19 integral x to the power of 18 blank d x minus 18 integral x to the power of negative 19 end exponent blank d x plus 14 integral x to the power of 1 over 13 end exponent blank d xequals 19 open parentheses fraction numerator 1 over denominator 18 plus 1 end fraction x to the power of 18 plus 1 end exponent plus C subscript 1 close parentheses minus 18 open parentheses fraction numerator 1 over denominator negative 19 plus 1 end fraction x to the power of negative 19 plus 1 end exponent plus C subscript 2 close parentheses plus 14 open parentheses fraction numerator 1 over denominator 1 over 13 plus 1 end fraction x to the power of 1 over 13 plus 1 end exponent plus C subscript 3 close parenthesesequals 19 open parentheses 1 over 19 x to the power of 19 plus C subscript 1 close parentheses minus 18 open parentheses fraction numerator 1 over denominator negative 18 end fraction x to the power of negative 18 end exponent plus C subscript 2 close parentheses plus 14 open parentheses fraction numerator 1 over denominator 14 over 13 end fraction x to the power of 14 over 13 end exponent plus C subscript 3 close parenthesesequals 19 times 1 over 19 x to the power of 19 plus 19 C subscript 1 minus 18 times fraction numerator 1 over denominator negative 18 end fraction x to the power of negative 18 end exponent minus 18 C subscript 2 plus 14 times 13 over 14 x to the power of 14 over 13 end exponent plus 14 C subscript 3equals x to the power of 19 plus 19 C subscript 1 plus x to the power of negative 18 end exponent minus 18 C subscript 2 plus 13 x to the power of 14 over 13 end exponent plus 14 C subscript 3equals x to the power of 19 plus 1 over x to the power of 18 plus 13 x root index 13 of x plus 19 C subscript 1 minus 18 C subscript 2 plus 14 C subscript 3 end style$

Misalkan maka

begin mathsize 14px style x to the power of 19 plus 1 over x to the power of 18 plus 13 x root index 13 of x plus 19 C subscript 1 minus 18 C subscript 2 plus 14 C subscript 3 equals x to the power of 19 plus 1 over x to the power of 18 plus 13 x root index 13 of x plus C end style

Jadi, jawaban yang tepat adalah E.