Roboguru

Hasil dari  adalah ...

Pertanyaan

Hasil dari 2 cubed cross times 2 squared cross times 8 to the power of negative 1 end exponent cross times 5 to the power of negative 1 end exponent adalah ...

  1. 2 over 5 

  2. 3 over 5 

  3. 4 over 5 

  4. 1 

Pembahasan Soal:

Kita sederhanakan terlebih dahulu 8 menjadi bilangan berpangkat, selanjutnya kita bisa gunakan sifat bilangan berpangkat untuk menyederhanakan soalnya, yaitu:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses a to the power of m close parentheses to the power of n end cell equals cell a to the power of m cross times n end exponent end cell row cell a to the power of m cross times a to the power of n end cell equals cell a to the power of m plus n end exponent end cell row cell a to the power of negative m end exponent end cell equals cell 1 over a to the power of m end cell end table

Maka,

table attributes columnalign right center left columnspacing 0px end attributes row cell 2 cubed cross times 2 squared cross times 8 to the power of negative 1 end exponent cross times 5 to the power of negative 1 end exponent end cell equals cell 2 cubed cross times 2 squared cross times open parentheses 2 cubed close parentheses to the power of negative 1 end exponent cross times 5 to the power of negative 1 end exponent end cell row blank equals cell open parentheses 2 cubed cross times 2 squared cross times 2 to the power of negative 3 end exponent close parentheses cross times 5 to the power of negative 1 end exponent end cell row blank equals cell 2 to the power of 3 plus 2 minus 3 end exponent cross times 5 to the power of negative 1 end exponent end cell row blank equals cell 2 squared cross times 1 fifth end cell row blank equals cell 4 over 5 end cell end table 

Jadi, jawaban yang tepat adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 19 Juli 2021

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