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Hasil dari adalah ...

Hasil dari begin mathsize 14px style limit as x rightwards arrow 0 of invisible function application fraction numerator open parentheses tan invisible function application 2 x cubed close parentheses open parentheses cos to the power of 4 invisible function application 3 x close parentheses plus open parentheses sin cubed invisible function application 3 x close parentheses open parentheses cos cubed invisible function application 2 x close parentheses over denominator x cubed open parentheses cos invisible function application 2 x close parentheses end fraction end style adalah ...

  1. space 

  2. space 

  3. 15 space 

  4. 29 space 

  5. 189 space 

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N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

jawaban yang tepat adalah D.

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Perhatikan bahwa Jadi, jawaban yang tepat adalah D.

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begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 0 of invisible function application fraction numerator left parenthesis tan invisible function application 2 x cubed right parenthesis left parenthesis cos to the power of 4 invisible function application 3 x right parenthesis plus left parenthesis sin cubed invisible function application 3 x right parenthesis left parenthesis cos cubed invisible function application 2 x right parenthesis over denominator x cubed left parenthesis cos invisible function application 2 x right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application left parenthesis fraction numerator open parentheses tan invisible function application 2 x cubed close parentheses open parentheses cos to the power of 4 invisible function application 3 x close parentheses over denominator x cubed open parentheses cos invisible function application 2 x close parentheses end fraction plus fraction numerator open parentheses sin cubed invisible function application 3 x close parentheses open parentheses cos cubed invisible function application 2 x close parentheses over denominator x cubed open parentheses cos invisible function application 2 x close parentheses end fraction right parenthesis end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application fraction numerator left parenthesis tan invisible function application 2 x cubed right parenthesis left parenthesis cos to the power of 4 invisible function application 3 x right parenthesis over denominator x cubed left parenthesis cos invisible function application 2 x right parenthesis end fraction plus limit as x rightwards arrow 0 of invisible function application fraction numerator left parenthesis sin cubed invisible function application 3 x right parenthesis left parenthesis cos cubed invisible function application 2 x right parenthesis over denominator x cubed left parenthesis cos invisible function application 2 x right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application fraction numerator tan invisible function application 2 x cubed over denominator x cubed end fraction times limit as x rightwards arrow 0 of invisible function application fraction numerator cos to the power of 4 invisible function application 3 x over denominator cos invisible function application 2 x end fraction plus limit as x rightwards arrow 0 of invisible function application fraction numerator sin cubed invisible function application 3 x over denominator x cubed end fraction times limit as x rightwards arrow 0 of invisible function application fraction numerator cos cubed invisible function application 2 x over denominator cos invisible function application 2 x end fraction end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application fraction numerator tan invisible function application 2 x cubed over denominator x cubed end fraction times open parentheses fraction numerator cos to the power of 4 invisible function application left parenthesis 3 times 0 right parenthesis over denominator cos invisible function application left parenthesis 2 times 0 right parenthesis end fraction close parentheses plus limit as x rightwards arrow 0 of invisible function application fraction numerator sin cubed invisible function application 3 x over denominator x cubed end fraction times open parentheses fraction numerator cos cubed invisible function application left parenthesis 2 times 0 right parenthesis over denominator cos invisible function application left parenthesis 2 times 0 right parenthesis end fraction close parentheses end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application fraction numerator tan invisible function application 2 x cubed over denominator x cubed end fraction times open parentheses 1 to the power of 4 over 1 close parentheses plus limit as x rightwards arrow 0 of invisible function application fraction numerator sin cubed invisible function application 3 x over denominator x cubed end fraction times open parentheses 1 cubed over 1 close parentheses end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application fraction numerator tan invisible function application 2 x cubed over denominator x cubed end fraction plus limit as x rightwards arrow 0 of invisible function application fraction numerator sin cubed invisible function application 3 x over denominator x cubed end fraction end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application fraction numerator tan invisible function application 2 x cubed over denominator x cubed end fraction plus limit as x rightwards arrow 0 of invisible function application open parentheses fraction numerator sin invisible function application 3 x over denominator x end fraction close parentheses cubed space end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application fraction numerator tan invisible function application 2 x cubed over denominator x cubed end fraction plus open parentheses limit as x rightwards arrow 0 of invisible function application fraction numerator sin invisible function application 3 x over denominator x end fraction close parentheses cubed space end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application open parentheses fraction numerator tan invisible function application 2 x cubed over denominator x cubed end fraction times 2 over 2 close parentheses plus open parentheses limit as x rightwards arrow 0 of invisible function application open parentheses fraction numerator sin invisible function application 3 x over denominator x end fraction times 3 over 3 close parentheses close parentheses cubed space end cell row blank equals cell limit as x rightwards arrow 0 of invisible function application open parentheses fraction numerator tan invisible function application 2 x cubed over denominator 2 x cubed end fraction times 2 close parentheses plus open parentheses limit as x rightwards arrow 0 of invisible function application open parentheses fraction numerator sin invisible function application 3 x over denominator 3 x end fraction times 3 close parentheses close parentheses cubed space end cell row blank equals cell 1 times 2 plus left parenthesis 1 times 3 right parenthesis cubed space end cell row blank equals cell 2 plus 27 end cell row blank equals 29 end table end style    

Jadi, jawaban yang tepat adalah D.

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