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Pertanyaan

Hasil dari ∫ x 2 − 16 ​ d x = ....

Hasil dari ....

  1. begin mathsize 14px style 1 half x square root of x squared minus 16 end root minus 2 ln invisible function application open vertical bar x plus square root of x squared minus 16 end root close vertical bar plus C end style 

  2. begin mathsize 14px style 1 half x square root of x squared minus 16 end root minus 8 ln invisible function application open vertical bar x plus square root of x squared minus 16 end root close vertical bar plus C end style 

  3. begin mathsize 14px style 1 half x square root of x squared minus 16 end root minus 8 ln invisible function application 1 fourth open vertical bar x plus square root of x squared minus 16 end root close vertical bar plus C end style 

  4. begin mathsize 14px style 2 x square root of x squared minus 16 end root minus 8 ln invisible function application 1 fourth open vertical bar x plus 2 square root of x squared minus 16 end root close vertical bar plus C end style 

  5. begin mathsize 14px style 2 x square root of x squared minus 16 end root minus 8 ln invisible function application open vertical bar x over 4 plus 1 fourth square root of x squared minus 16 end root close vertical bar plus C end style 

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S. Difhayanti

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Prof. Dr. Hamka

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

jawaban yang tepat adalah C.

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Pembahasan

Ingat kembali integral berikut ini! Maka diperoleh Jadi, jawaban yang tepat adalah C.

Ingat kembali integral berikut ini!

begin mathsize 14px style integral square root of x squared minus a squared end root blank d x equals a squared open parentheses fraction numerator x over a square root of fraction numerator x squared minus a squared over denominator a end fraction end root over denominator 2 end fraction minus fraction numerator ln invisible function application open vertical bar x over a plus square root of fraction numerator x squared minus a squared over denominator a end fraction end root close vertical bar over denominator 2 end fraction close parentheses plus C end style 

Maka diperoleh 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral square root of x squared minus 16 end root blank d x end cell equals cell integral square root of x squared minus 4 squared end root blank d x end cell row blank equals cell 4 squared open parentheses fraction numerator x over 4 times fraction numerator square root of x squared minus 4 squared end root over denominator 4 end fraction over denominator 2 end fraction minus fraction numerator ln invisible function application open vertical bar x over 4 plus fraction numerator square root of x squared minus 4 squared end root over denominator 4 end fraction close vertical bar over denominator 2 end fraction close parentheses plus C end cell row blank equals cell 16 times fraction numerator open parentheses x over 16 square root of x squared minus 16 end root minus ln invisible function application open vertical bar x over 4 plus 1 fourth square root of x squared minus 16 end root close vertical bar close parentheses over denominator 2 end fraction plus C end cell row blank equals cell 8 open parentheses x over 16 square root of x squared minus 16 end root minus ln invisible function application open vertical bar x over 4 plus 1 fourth square root of x squared minus 16 end root close vertical bar close parentheses plus C end cell row blank equals cell 1 half x square root of x squared minus 16 end root minus 8 ln invisible function application 1 fourth open vertical bar x plus square root of x squared minus 16 end root close vertical bar plus C end cell row blank blank blank end table end style 

Jadi, jawaban yang tepat adalah C.

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