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Pertanyaan

Hasil dari ∫ 16 + x 2 ​ d x = ....

Hasil dari ....

  1. begin mathsize 14px style 1 half x square root of 16 plus x squared end root minus 16 ln invisible function application 1 fourth open vertical bar square root of 16 plus x squared end root plus x close vertical bar plus C end style 

  2. size 14px 1 over size 14px 2 size 14px x square root of size 14px 16 size 14px plus size 14px x to the power of size 14px 2 end root size 14px plus size 14px 8 size 14px ln size 14px invisible function application size 14px 1 over size 14px 4 begin mathsize 14px style vertical line square root of 16 plus x squared end root plus x vertical line end style size 14px plus size 14px C    

  3. begin mathsize 14px style 1 fourth x square root of 16 plus x squared end root minus 4 ln invisible function application 1 fourth open vertical bar square root of 16 plus x squared end root plus x close vertical bar plus C space end style 

  4. begin mathsize 14px style 2 x square root of 16 plus x squared end root minus 8 ln invisible function application 1 fourth open vertical bar square root of 16 plus x squared end root plus x close vertical bar plus C end style 

  5. begin mathsize 14px style 2 x square root of 16 plus x squared end root minus 16 ln invisible function application 1 fourth open vertical bar square root of 16 plus x squared end root plus x close vertical bar plus C end style 

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A. Khairunisa

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.

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Pembahasan

Ingat kembali integral berikut ini! Maka diperoleh Jadi, jawaban yang tepat adalah B.

Ingat kembali integral berikut ini!

begin mathsize 14px style integral square root of a squared plus x squared end root blank d x equals a squared open parentheses fraction numerator square root of fraction numerator a squared plus x squared over denominator a end fraction end root times x over a over denominator 2 end fraction plus fraction numerator ln invisible function application open vertical bar square root of fraction numerator a squared plus x squared over denominator a end fraction end root plus x over a close vertical bar over denominator 2 end fraction close parentheses plus C end style 

Maka diperoleh

begin mathsize 14px style integral square root of 16 plus x squared end root blank d x equals integral square root of 4 squared plus x squared end root blank d x equals 4 squared open parentheses fraction numerator fraction numerator square root of 4 squared plus x squared end root over denominator 4 end fraction times x over 4 over denominator 2 end fraction plus fraction numerator ln invisible function application open vertical bar fraction numerator square root of 4 squared plus x squared end root over denominator 4 end fraction plus x over 4 close vertical bar over denominator 2 end fraction close parentheses plus C equals 16 times fraction numerator open parentheses x over 16 square root of 16 plus x squared end root plus ln invisible function application 1 fourth open vertical bar square root of 16 plus x squared end root plus x close vertical bar close parentheses over denominator 2 end fraction plus C equals 8 open parentheses x over 16 square root of 16 plus x squared end root plus ln invisible function application 1 fourth open vertical bar square root of 16 plus x squared end root plus x close vertical bar close parentheses plus C equals 1 half x square root of 16 plus x squared end root plus 8 ln invisible function application 1 fourth open vertical bar square root of 16 plus x squared end root plus x close vertical bar plus C end style    

Jadi, jawaban yang tepat adalah B.

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