Roboguru

Harga pH asam formiat 0,1 M (Ka = ) adalah ...

Pertanyaan

Harga pH asam formiat 0,1 M (Ka = 1 cross times 10 to the power of negative sign 7 end exponent) adalah ...

Pembahasan Soal:

menentukan nilai H+ :

H to the power of plus sign equals square root of K subscript a cross times M subscript a end root H to the power of plus sign equals square root of 10 to the power of negative sign 7 end exponent cross times 0 comma 1 end root H to the power of plus sign equals square root of 10 to the power of negative sign 7 end exponent cross times 10 to the power of negative sign 1 end exponent end root H to the power of plus sign equals square root of 10 to the power of negative sign 8 end exponent end root H to the power of plus sign equals 10 to the power of negative sign 4 end exponent

menentukan pH :

pH space equals space minus sign log space H to the power of plus sign pH space equals space minus sign log space 10 to the power of negative sign 4 end exponent pH space equals space 4 

JadipH asam formiat 0,1 M adalah 4.

 

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

A. Nurul

Mahasiswa/Alumni UIN Syarif Hidayatullah Jakarta

Terakhir diupdate 04 Juni 2021

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Pertanyaan yang serupa

Jika 0,05 mol  dilarutkan dalam air terdapat  ion . Jumlah air yang digunakan . . . . L

Pembahasan Soal:

Asam asetat merupakan asam lemah yang mana terurai sebagian dalam air.

Maka, untuk menentukan Volume air yang digunakan, langkah pertama adalah menentukan konsentrasi asam asetat sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row cell H to the power of plus sign end cell equals cell square root of Ka cross times open square brackets C H subscript 3 C O O H close square brackets end root end cell row cell 0 comma 8 cross times 10 to the power of negative sign 4 end exponent M end cell equals cell square root of 1 comma 6 cross times 10 to the power of negative sign 5 end exponent cross times open square brackets C H subscript 3 C O O H close square brackets end root end cell row cell open square brackets C H subscript 3 C O O H close square brackets end cell equals cell fraction numerator 0 comma 64 cross times 10 to the power of negative sign 8 end exponent M over denominator 1 comma 6 cross times 10 to the power of negative sign 5 end exponent end fraction end cell row blank equals cell 4 cross times 10 to the power of negative sign 4 end exponent M end cell end table 

Maka, volume air yang dibutuhkan adalah pembagian antara mol dengan konsentrasi asam asetat sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row V equals cell mol over M end cell row blank equals cell fraction numerator 0 comma 05 space mol over denominator 4 cross times 10 to the power of negative sign 4 end exponent M end fraction end cell row blank equals cell 125 space L end cell end table 

Maka, volume air yang digunakan adalah 125 liter

0

Roboguru

Terdapat 100 mL larutan  0,1 M yang memiliki . Maka nilai  dan  adalah ....

Pembahasan Soal:

Larutan begin mathsize 14px style C H subscript 3 C O O H end style merupakan asam lemah, maka konsentrasi ion begin mathsize 14px style H to the power of plus sign end style -nya dapat ditentukan dari:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a cross times M subscript a end root end cell row blank equals cell square root of 1 comma 8 cross times 10 to the power of negative sign 5 end exponent cross times 0 comma 1 end root end cell row blank equals cell square root of 1 comma 8 cross times 10 to the power of negative sign 6 end exponent end root end cell row blank equals cell 1 comma 34 cross times 10 to the power of negative sign 3 end exponent end cell end table end style 

begin mathsize 14px style alpha end style merupakan derajat disosiasi, dapat dicari dengan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell alpha cross times M subscript a end cell row cell 1 comma 34 cross times 10 to the power of negative sign 3 end exponent end cell equals cell alpha cross times 0 comma 1 end cell row alpha equals cell 1 comma 34 cross times 10 to the power of negative sign 2 end exponent end cell end table end style  

Jadi, jawaban yang benar adalah A.

0

Roboguru

Diketahui beberapa larutan asam sebagai berikut : 1) 100 ml larutan   2) 100 ml larutan   3) 100 ml larutan   4) 100 ml larutan   5) 100 ml larutan   Larutan yang mempunyai pH paling rendah ditunjukka...

Pembahasan Soal:

1) 100 ml larutan begin mathsize 14px style H subscript 2 S O subscript 4 space 0 comma 02 space M end style 

H subscript 2 S O subscript 4 yields 2 H to the power of plus sign and S O subscript 4 to the power of negative sign 2 end exponent open square brackets H to the power of plus sign close square brackets equals 2 cross times M space H subscript 2 S O subscript 4 space space space space space space space space space equals 2 cross times 0 comma 02 space M space space space space space space space space space equals 0 comma 04 space M pH equals minus sign log open square brackets H to the power of plus sign close square brackets space space space space equals minus sign log left parenthesis 0 comma 04 right parenthesis space space space space equals minus sign log left parenthesis 4 cross times 10 to the power of negative sign 2 end exponent right parenthesis space space space space equals 2 minus sign log space 4 space   


2) 100 ml larutan begin mathsize 14px style H Cl O subscript 4 space 0 comma 03 space M end style 

H Cl O subscript 4 yields H to the power of plus sign and Cl O subscript 4 to the power of minus sign open square brackets H to the power of plus sign close square brackets double bond M space H Cl O subscript 4 equals 0 comma 03 space M pH equals minus sign log open square brackets H to the power of plus sign close square brackets space space space space equals minus sign log left parenthesis 0 comma 03 right parenthesis space space space space equals minus sign log left parenthesis 3 cross times 10 to the power of negative sign 2 end exponent right parenthesis space space space space equals 2 minus sign log space 3   


3) 100 ml larutan begin mathsize 14px style H N O subscript 3 space 0 comma 01 space M end style 

H N O subscript 3 yields H to the power of plus sign and N O subscript 3 to the power of minus sign open square brackets H to the power of plus sign close square brackets double bond M space H N O subscript 3 equals 0 comma 01 space M pH equals minus sign log open square brackets H to the power of plus sign close square brackets space space space space equals minus sign log left parenthesis 0 comma 01 right parenthesis space space space space equals minus sign log left parenthesis 10 to the power of negative sign 2 end exponent right parenthesis space space space space equals 2  


4) 100 ml larutan begin mathsize 14px style H Cl space 0 comma 05 space M end style 

H Cl yields H to the power of plus sign and Cl to the power of minus sign open square brackets H to the power of plus sign close square brackets double bond M space H Cl equals 0 comma 05 space M pH equals minus sign log open square brackets H to the power of plus sign close square brackets space space space space equals minus sign log left parenthesis 0 comma 05 right parenthesis space space space space equals minus sign log left parenthesis 5 cross times 10 to the power of negative sign 2 end exponent right parenthesis space space space space equals 2 minus sign log space 5  


5) 100 ml larutan begin mathsize 14px style H Br space 0 comma 04 space M end style 

H Br yields H to the power of plus sign and Br to the power of minus sign open square brackets H to the power of plus sign close square brackets double bond M space Br equals 0 comma 04 space M pH equals minus sign log open square brackets H to the power of plus sign close square brackets space space space space equals minus sign log left parenthesis 0 comma 04 right parenthesis space space space space equals minus sign log left parenthesis 4 cross times 10 to the power of negative sign 2 end exponent right parenthesis space space space space equals 2 minus sign log space 4  

Jadi, larutan yang memiliki pH paling rendah adalah larutan 4).

0

Roboguru

Tentukan pH larutan  ...

Pembahasan Soal:

Rumus penyelesaian:
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log square root of Ka cross times Ma end root end cell row blank equals cell negative sign log square root of 1 cross times 10 to the power of negative sign 5 end exponent cross times 0 comma 01 end root end cell row blank equals cell negative sign log square root of 1 cross times 10 to the power of negative sign 7 end exponent end root end cell row blank equals cell negative sign log space 1 cross times 10 to the power of negative sign 3 comma 5 end exponent end cell row blank equals cell 3 comma 5 end cell end table end style 
 

Jadi, dapat disimpulkan pH larutan yaitu 3,5.

0

Roboguru

Harga pH larutan HCOOH 0,01 M () adalah ....

Pembahasan Soal:

Nilai pH asam lemah ditentukan berdasarkan perhitungan berikut:

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a cross times M subscript a end root end cell row blank equals cell square root of 1 comma 8 cross times 10 to the power of negative sign 4 end exponent cross times 10 to the power of negative sign 2 end exponent end root end cell row blank equals cell square root of 1 comma 8 end root cross times 10 to the power of negative sign 3 end exponent end cell row blank blank blank row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log space square root of 1 comma 8 end root cross times 10 to the power of negative sign 3 end exponent end cell row blank equals cell 3 minus sign log space square root of 1 comma 8 end root end cell end table end style 


Tidak ada opsi jawaban yang benar.

Jadi, jawaban yang benar adalah begin mathsize 14px style 3 minus log square root of 1 comma 8 end root end style.

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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