Pertanyaan

Garis a melalui titik dan .Jika garis a tegak lurus dengan garis b dan gradien garis b adalah 9 11 ,maka nilai t adalah ....

Garis a melalui titik $begin mathsize 14px style open parentheses fraction numerator 2 t over denominator 3 end fraction comma negative 4 over 7 close parentheses end style$ dan $begin mathsize 14px style open parentheses negative 2 over 3 comma negative fraction numerator 5 t over denominator 11 end fraction close parentheses end style$ . Jika garis a tegak lurus dengan garis b dan gradien garis b adalah $\frac{11}{9}$ , maka nilai t adalah ....

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Klaim

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

Diketahui garis a tegak lurus dengan garis b , maka kita peroleh Kemudian, misalkan dan , maka

Diketahui garis a tegak lurus dengan garis b, maka kita peroleh

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript a times m subscript b end cell equals cell negative 1 end cell row cell m subscript a times 11 over 9 end cell equals cell negative 1 end cell row cell m subscript a end cell equals cell negative 9 over 11 end cell end table end style

Kemudian, misalkan $begin mathsize 14px style open parentheses x subscript 1 comma y subscript 1 close parentheses equals open parentheses fraction numerator 2 t over denominator 3 end fraction comma negative 4 over 7 close parentheses end style$ dan $begin mathsize 14px style open parentheses x subscript 2 comma y subscript 2 close parentheses equals open parentheses negative 2 over 3 comma negative fraction numerator 5 t over denominator 11 end fraction close parentheses end style$ , maka

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript a end cell equals cell fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction end cell row cell negative 9 over 11 end cell equals cell fraction numerator negative fraction numerator 5 t over denominator 11 end fraction minus open parentheses negative 4 over 7 close parentheses over denominator negative 2 over 3 minus fraction numerator 2 t over denominator 3 end fraction end fraction end cell row cell negative 9 over 11 end cell equals cell fraction numerator fraction numerator negative 35 t plus 44 over denominator 77 end fraction over denominator fraction numerator negative 2 minus 2 t over denominator 3 end fraction end fraction end cell row cell negative 9 open parentheses fraction numerator negative 2 minus 2 t over denominator 3 end fraction close parentheses end cell equals cell 11 open parentheses fraction numerator negative 35 t plus 44 over denominator 77 end fraction close parentheses end cell row cell 6 plus 6 t end cell equals cell fraction numerator negative 35 t plus 44 over denominator 7 end fraction end cell row cell 7 open parentheses 6 plus 6 t close parentheses end cell equals cell negative 35 t plus 44 end cell row cell 42 plus 42 t end cell equals cell negative 35 t plus 44 end cell row cell 77 t end cell equals 2 row t equals cell 2 over 77 end cell end table end style$