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Garam kalium asetat C H 3 ​ COO K dapat dibuat dengan mereaksikan 20 mL larutan asam asetat 0,5 M dan 20 mL larutan kalium hidroksida 0,5 M dengan reaksi: C H 3 ​ COO H ( a q ) + K O H ( a q ) → C H 3 ​ COO K ( a q ) + H 2 ​ O ( l ) . Besarnya pH larutan setelah dicampur adalah ... ( K w = 1.1 0 − 14 , K a C H 3 ​ COO H = 1.1 0 − 5 )

Garam kalium asetat dapat dibuat dengan mereaksikan 20 mL larutan asam asetat 0,5 M dan 20 mL larutan kalium hidroksida 0,5 M dengan reaksi: . Besarnya pH larutan setelah dicampur adalah ...

  1. 5,5 - log 5

  2. 5,5 + log 5

  3. 8,5 - log 5

  4. 8,5 + log 5

  5. 11 + log 5

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I. Solichah

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Pada reaksi, didapatkan :

Pada reaksi, didapatkan :

 

space space space space space space space space space space space space space space C H subscript 3 C O O H space space space plus space space space space K O H space space space space space space space rightwards arrow space C H subscript 3 C O O K space space space space space plus space space space space space H subscript 2 O  M u l a space space space space space space space space 10 space m m o l space space space space space space space space space space 10 space m m o l  R e a k s i space space minus 10 m m o l space space space space space space minus 10 space m m o l space space space space space space space space space space plus 10 space m m o l space space space space space space space space space plus 10 space m m o l  S i s a space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space 10 space m m o l space space space space space space space space space space space space space 10 space m m o l    left square bracket C H subscript 3 C O O K right square bracket equals fraction numerator m o l over denominator V subscript t o t a l end subscript end fraction equals fraction numerator 10 space m m o l over denominator 40 space m L end fraction equals 0 comma 25 space M  C H subscript 3 C O O K space a d a l a h space g a r a m space b a s a comma space s e h i n g g a semicolon  left square bracket O H to the power of minus right square bracket equals square root of fraction numerator K w cross times left square bracket g a r a m right square bracket over denominator K a end fraction end root  space space space space space space space space space space space equals square root of fraction numerator 10 to the power of negative 14 end exponent cross times 0 comma 25 over denominator 10 to the power of negative 5 end exponent end fraction end root  space space space space space space space space space space space equals square root of 25 cross times 10 to the power of negative 11 end exponent end root  space space space space space space space space space space space equals 5 cross times 10 to the power of negative 5 comma 5 end exponent space M    p O H equals negative log space 5 cross times 10 to the power of negative 5 comma 5 end exponent  space space space space space space space space space equals 5 comma 5 minus log space 5    p H equals 14 minus p O H  space space space space space space equals 14 minus left parenthesis 5 comma 5 minus log space 5 right parenthesis  space space space space space space space equals 8 comma 5 plus log space 5

51

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Tetapan hidrolisis NaBrO sebesar .... ( K a ​ HBrO = 2 × 1 0 − 5 )

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